Question

当我在fileName中包含zipParameter和putNextEntry()时：

ZipOutputStream.putNextEntry(fileName, zipParameter);

显示错误：

The method putNextEntry(ZipEntry) in the type ZipOutputStream is not applicable for the arguments (String, ZipParameters).

Answer 1

希望您的文件名未声明为String。它应该是 FileOutputStream 作为第一个参数，该参数应获取 File 。

File zipFile = new File("file.txt");
ZipOutputStream zos = new ZipOutputStream( new FileOutputStream(zipFile));
try
{
 ZipEntry entry = new ZipEntry("myFile.txt"); // put file inside 
 zos.putNextEntry(entry);
} catch (FileNotFoundException e)
{
 e.printStackTrace();
} catch (IOException e)
{
 e.printStackTrace();
} finally
{
 zos.closeEntry();
 zos.close();
}

尝试一下，可能会有帮助

Answer 2

这是java.util.zip.ZipOutputStream的putNextEntry的方法签名，该方法签名仅接受ZipEntry作为参数：

 /**
     * Begins writing a new ZIP file entry and positions the stream to the
     * start of the entry data. Closes the current entry if still active.
     * The default compression method will be used if no compression method
     * was specified for the entry, and the current time will be used if
     * the entry has no set modification time.
     * @param e the ZIP entry to be written
     * @exception ZipException if a ZIP format error has occurred
     * @exception IOException if an I/O error has occurred
     */

    public void putNextEntry(ZipEntry e) throws IOException {
        ensureOpen();
        if (current != null) {
            closeEntry();       // close previous entry
        }
       ....

如何解决putNextEntry（ZipEntry）不接受ZipParameters的问题？

2 个答案: