Question

我正在编写一个处理文件中字符串的程序。我只想将SUB =X'1D'上方的文字（字符串，例如=X'1D' BYTE X'1D'组合成' LTORG'）添加到我的测试文件中。

问题是我收集了每个LTORG上方的文字作为列表，并将它们作为列表插入。我想一次插入一个文字。

我的输出是：

[' START 100', " SUB =X'1D'", ' LTORG', '["=X\'1D\' BYTE X\'1D\'"]', ' RESW 
   20', " SUB =X'0259'", " ADD =C'12345'", " MUL =X'4356'", " SUB =X'69'", ' 
   LTORG', '["=X\'0259\' BYTE X\'0259\'", "=C\'12345\' BYTE C\'12345\'", 
   "=X\'4356\' BYTE X\'4356\'", "=X\'69\' BYTE X\'69\'"]', " ADD =C'05'", ' 
   END EXA']

def handle_LTORG(self, testfile):

    myfile.testfile = testfile

    for index, line in enumerate(myfile.testfile):
        line = line.split(" ", 3)
        if len(line) > 2:
            if line[2].startswith("=X") or line[2].startswith("=C"):
                raw_literal = line[2]
                instruction = 'BYTE'
                operand = line[2][1:]
                literal = [raw_literal, instruction, operand]
                literal = ' '.join(literal)
                myfile.literals.append(literal)
        if line[1] == 'LTORG':
            if myfile.literals is not None:
                myfile.testfile.insert(index + 1, str(myfile.literals))
                myfile.literals.pop(0)

倒数第二行主要产生此问题。它将收集到的文字添加到列表中，并将其作为打包列表插入，而不是每行一个字符串。

我希望它看起来像这样：

[' START 100', " SUB =X'1D'", ' LTORG', '"=X'1D' BYTE X'1D'"', ' RESW 20', " SUB =X'0259'", " ADD =C'12345'", " MUL =X'4356'", " SUB =X'69'", ' LTORG', '"=X'0259' BYTE X'0259'", "=C'12345' BYTE C'12345'", "=X'4356' BYTE X'4356'", "=X'69' BYTE X'69'", " ADD =C'05'", ' END EXA']

Answer 1

我会在How to make a flat list out of list of lists?

中尝试使用最常用的评论

list = ['whatever',['1','2','3'],'3er']
flat_list = []
for member in list:
    if type(member) is list:
        for item in member:
            flat_list.append(item)
    else:
        flat_list.append(member)

Answer 2

您要执行的操作是两个操作的组合：

首先，您需要将字符串文字中的所有列表转换为 literal_eval模块中的ast使用实际列表。
然后，您需要整理列表。

下面是使过程降级的代码：

AlertDialog.Builder builder = new AlertDialog.Builder(getMyActivity());
     AlertDialog dialog = builder.create();
            dialog.requestWindowFeature(Window.FEATURE_NO_TITLE);
            dialog.getWindow().setLayout(MATCH_PARENT, WRAP_CONTENT);
            dialog.getWindow().getAttributes().windowAnimations = R.style.DialogAnimation; 
            WindowManager.LayoutParams wmlp = dialog.getWindow().getAttributes();
            dialog.getWindow().setGravity(Gravity.BOTTOM);


            wmlp.gravity = Gravity.BOTTOM ;
            dialog.show();

输出：

from ast import literal_eval
inlist = [' START 100', " SUB =X'1D'", ' LTORG', '["=X\'1D\' BYTE X\'1D\'"]', ' RESW    20', " SUB =X'0259'", " ADD =C'12345'", " MUL =X'4356'", " SUB =X'69'", '    LTORG', '["=X\'0259\' BYTE X\'0259\'", "=C\'12345\' BYTE C\'12345\'",    "=X\'4356\' BYTE X\'4356\'", "=X\'69\' BYTE X\'69\'"]', " ADD =C'05'", '    END EXA']
inlist = [literal_eval(elem) if elem[0] == '[' and elem[-1] == ']' else elem for elem in inlist]
outlist = []
for elem in inlist:
     if isinstance(elem,list):
          for item in elem:
               outlist.append(item)
     else:
          outlist.append(elem)
print(outlist)

Answer 3

更新：解决了while循环的问题。随时发布建议！

    def handle_LTORG(self, testfile):

    myfile.testfile = testfile

    for index, line in enumerate(myfile.testfile):
        line = line.split(" ", 3)
        if len(line) > 2:
            if line[2].startswith("=X") or line[2].startswith("=C"):
                raw_literal = line[2]
                instruction = 'BYTE'
                operand = line[2][1:]
                literal = [raw_literal, instruction, operand]
                literal = ' '.join(literal)
                myfile.literals.append(literal)
        if line[1] == 'LTORG':
            if myfile.literals:
                i = 'hi'
                while len(i) > 0:
                    i = myfile.literals[-1]
                    myfile.testfile.insert(index+1, str(i))
                    myfile.literals.pop()
                    if len(myfile.literals) == 0:
                        break

    return myfile.testfile

将包含字符串的列表和嵌套的字符串列表拆分为一个平面列表

3 个答案: