Question

$query = $this->restaurant->join('reviews', 'reviews.restaurant_id', '=', 'restaurants.id');
        $query = $user_id == null ? $query : $query->where("user_id", $user_id);

        $query = $query->select('restaurants.*')
                        ->selectRaw('ROUND(AVG(reviews.rating) as average_rating)')
                        ->groupBy('restaurants.id')
                        ->havingRaw('AVG(reviews.rating) >= ?', [$request->from_rating])
                        ->havingRaw('AVG(reviews.rating) <= ?', [$request->to_rating])
                        ->orderByDesc("average_rating")
                        ->paginate(
                            $this->perPage, 
                            ['id', 'name', 'image', 'description', 'filesystem', 'created_at'], 
                            'page', 
                            $request->page
                        );

        return $query;

我的查询如下所示。事情是我想使用ROUND。当我运行它时，它告诉我

SQLSTATE [42000]：语法错误或访问冲突：1583错误调用本机函数“ round”（SQL：选择）中的参数 restaurants。*，ROUND（AVG（reviews.rating）as average_rating）来自 restaurants上的reviews内部联接reviews。restaurant_id = restaurants。id由restaurants。id分组 AVG（reviews.rating）> = 0和AVG（reviews.rating）<= 5阶 average_rating描述限制5偏移量0）

谁能告诉我为什么？

Answer 1

round部分：

ROUND(AVG(reviews.rating) as average_rating)

应该看起来像这样：

ROUND(AVG(reviews.rating)) as average_rating

sql laravel中不正确的参数来回合

1 个答案: