Question

我正在编写一个应用程序，并且想对其执行推送通知，以通知用户发生了什么事。我环顾四周，找到了所需的代码，但不确定如何解决我面临的问题。可能是因为代码已过期或不正确。这是我在说的：

public class FirebaseInstanceIDService extends FirebaseInstanceIdService implements Constants

public class FireBaseMessagingService extends FirebaseMessagingService implements Constants

删除工具常量会导致其损坏，并可以在需要调用的清单中使用。

我尝试删除该工具，但是会导致另一个错误，如果我删除了该工具而只留下了“ class”，它就不会被公开，但我无法调用该应用的清单

ID服务

import android.util.Log;
import android.view.View;

import com.google.android.gms.common.internal.Constants;
import com.google.firebase.iid.FirebaseInstanceId;
import com.google.firebase.iid.FirebaseInstanceIdService;

 public class MyFirebaseInstanceIDService extends FirebaseInstanceIdService implements Constants {
    private static final String TAG = "MyFirebaseIIDService";

    @Override
    public void onTokenRefresh() {
        // Get updated InstanceID token.
        String refreshedToken = FirebaseInstanceId.getInstance().getToken();
        Log.d(TAG, "Refreshed token: " + refreshedToken);
    }
}

会议服务

import android.app.NotificationManager;
import android.app.PendingIntent;
import android.content.Context;
import android.media.RingtoneManager;
import android.net.Uri;
import android.support.v4.app.NotificationCompat;
import android.util.Log;

import com.google.android.gms.common.internal.Constants;
import com.google.firebase.messaging.FirebaseMessagingService;
import com.google.firebase.messaging.RemoteMessage;

import java.util.Map;

public class FireBaseMessagingService extends FirebaseMessagingService implements Constants {
    private static final String TAG = "MyFirebaseMsgService";
    private static int count = 0;
    @Override
    public void onMessageReceived(RemoteMessage remoteMessage) {
        //Displaying data in log
        //It is optional
        Log.d(TAG, "Notification Message TITLE: " + remoteMessage.getNotification().getTitle());
        Log.d(TAG, "Notification Message BODY: " + remoteMessage.getNotification().getBody());
        Log.d(TAG, "Notification Message DATA: " + remoteMessage.getData().toString());
//Calling method to generate notification
        sendNotification(remoteMessage.getNotification().getTitle(),
                remoteMessage.getNotification().getBody(), remoteMessage.getData());
    }
    //This method is only generating push notification
    private void sendNotification(String messageTitle, String messageBody, Map<String, String> row) {
        PendingIntent contentIntent = null;
        Uri defaultSoundUri = RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
        NotificationCompat.Builder notificationBuilder = new NotificationCompat.Builder(this)
                .setContentTitle(messageTitle)
                .setContentText(messageBody)
                .setAutoCancel(true)
                .setSound(defaultSoundUri)
                .setContentIntent(contentIntent);
        NotificationManager notificationManager =
                (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
        notificationManager.notify(count, notificationBuilder.build());
        count++;
    }
}

这是我要使用的完整代码

我希望它能够将其用于推送通知。但是，如果出现错误，将无法使用。

Answer 1

要使Firebase推送通知在Android上正常工作，以下是您需要在Android应用上执行的操作，

将firebase依赖项添加到gradle文件中，并将从firebase控制台下载的google-services.json文件放入您的项目中。
```
compile "com.google.firebase:firebase-messaging:17.3.4"
```

创建一个用于接收推送令牌和通知有效载荷的接收器。

public class FCMNotificationReceiver extends FirebaseMessagingService 
{
  @Override
  public void onNewToken(String s) {
      super.onNewToken(s);
      // send token to your server.

  }

 @Override
  public void onMessageReceived(RemoteMessage remoteMessage) {
      super.onMessageReceived(remoteMessage);
      // use your own logic here to process notification. For example, 
      sendNotification(remoteMessage.getNotification().getTitle(),
          remoteMessage.getNotification().getBody(), remoteMessage.getData());
  }

}

在清单中注册以上服务


 <service android:name=".FCMNotificationReceiver">
             <intent-filter>
                 <action android:name="com.google.firebase.MESSAGING_EVENT"/>
             </intent-filter>
 </service>

（可选）您还可以在应用开始获取推送令牌时调用firebase。


    FirebaseInstanceId.getInstance().getInstanceId().addOnSuccessListener(new OnSuccessListener<InstanceIdResult>() {
                @Override
                public void onSuccess(InstanceIdResult instanceIdResult) {
                    String mToken = instanceIdResult.getToken();
                    // send token to your server.

                }
            });

如何修复Firebase Instant ID服务

1 个答案: