Question

以下是我们应完成的国家/地区列表将输入作为国家名称并将输出发送为的功能逗号分隔该特定国家/地区中所有州的firstLetter值

样本输入-findCountryFunction（“ France”）输出-“ N，O，P，P”

  let countryData = {
  "France": ["Nouvelle-Aquitaine",
    "Occitanie",
    "Pays de la Loire",
    "Provence-Alpes-Côte d'Azur"
  ],
  "India": ["West Bengal",
    "Andhrapradesh",
    "Hariyana"
  ],
  "Bangladesh": ["Dhaka",
    "Khulna",
    "Barishal"
  ]
};




let findCountryFunction = (stateName)=>{
    for(let info in countryData){
        if(countryData[info] == stateName){
            console.log(countryData[info][0]);
        }

    }

};

findCountryFunction("France");

Answer 1

这无效if(countryData[info] == stateName){，因为info已经具有属性值。检查for...in的工作方式。

您应该拥有：

function findCountryFunction(stateName) {
  let result = [];
  for (let info in countryData[stateName]) {
    result.push(countryData[stateName][info].charAt(0))

  }

  console.log(result.join());
}

let countryData = {
  "France": ["Nouvelle-Aquitaine",
    "Occitanie",
    "Pays de la Loire",
    "Provence-Alpes-Côte d'Azur"
  ],
  "India": ["West Bengal",
    "Andhrapradesh",
    "Hariyana"
  ],
  "Bangladesh": ["Dhaka",
    "Khulna",
    "Barishal"
  ]
};

findCountryFunction('France');

Answer 2

你可以做

let countryData = {
  "France": ["Nouvelle-Aquitaine",
    "Occitanie",
    "Pays de la Loire",
    "Provence-Alpes-Côte d'Azur"
  ],
  "India": ["West Bengal",
    "Andhrapradesh",
    "Hariyana"
  ],
  "Bangladesh": ["Dhaka",
    "Khulna",
    "Barishal"
  ]
};
var country = countryData['France'];


for (idx in country) {
  var letter = country[idx][0];
  console.log(letter);
}

然后遍历country变量以获取数组中每个元素的首字母

函数将输入作为国家/地区名称，并将输出作为逗号分隔，发送该特定国家/地区中所有州的firstLetter值

2 个答案: