我为32位WPF应用程序长时间使用此代码没有任何问题。 现在,我第一次编译64位应用程序时,此启动类无法正常工作。
有某些原因为什么不起作用? 没有错误,我检查注册表,并且注册表项不存在。 我非常感谢您提供的任何帮助,如有需要,请进行修复,发表评论。
非常感谢!
public class StartUpManager
{
public static void AddApplicationToCurrentUserStartup()
{
using (RegistryKey key = Registry.CurrentUser.OpenSubKey ("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run", true))
{
key.SetValue("My ApplicationStartUpDemo", "\"" + System.Reflection.Assembly.GetExecutingAssembly().Location + "\"");
}
}
public static void AddApplicationToAllUserStartup()
{
using (RegistryKey key = Registry.LocalMachine.OpenSubKey("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run", true))
{
key.SetValue("My ApplicationStartUpDemo", "\"" + System.Reflection.Assembly.GetExecutingAssembly().Location + "\"");
}
}
public static void RemoveApplicationFromCurrentUserStartup()
{
using (RegistryKey key = Registry.CurrentUser.OpenSubKey("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run", true))
{
key.DeleteValue("My ApplicationStartUpDemo", false);
}
}
public static void RemoveApplicationFromAllUserStartup()
{
using (RegistryKey key = Registry.LocalMachine.OpenSubKey("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run", true))
{
key.DeleteValue("My ApplicationStartUpDemo", false);
}
}
public static bool IsUserAdministrator()
{
//bool value to hold our return value
bool isAdmin;
try
{
//get the currently logged in user
WindowsIdentity user = WindowsIdentity.GetCurrent();
WindowsPrincipal principal = new WindowsPrincipal(user);
isAdmin = principal.IsInRole(WindowsBuiltInRole.Administrator);
}
catch (UnauthorizedAccessException ex)
{
isAdmin = false;
}
catch (Exception ex)
{
isAdmin = false;
}
return isAdmin;
}
}
Update1:我使用的是AddApplicationToAllUserStartup()
密钥创建于
计算机\ HKEY_LOCAL_MACHINE \ SOFTWARE \ Microsoft \ Windows \ CurrentVersion \ Run
复制不会开始,真的很奇怪。
Update2: 好吧,很明显,还有另一种方法可以调用64位应用程序,并且此代码仅适用于32位。 我只是用这个类创建一个干净的wpf应用程序,如果我编译64bit不能正常工作,而我的copile 32bit可以正常工作!
更新3,解决方案!
不要问我为什么,但是要强制使用32位注册表才能正常工作。
"SOFTWARE\\WOW6432Node\\Microsoft\\Windows\\CurrentVersion\\Run"
这真的很奇怪,不知道为什么会发生,但这已解决,现在我的64位应用程序开始完美!
如果有人对这个问题有正确的答案,我很想知道为什么会发生。 修复:
class StartUpManager
{
public static RegistryKey key = RegistryKey.OpenBaseKey(RegistryHive.LocalMachine, RegistryView.Registry32); //Dont think is necesary, but just in case
public static void AddApplicationToCurrentUserStartup()
{
using (key = Registry.CurrentUser.OpenSubKey("SOFTWARE\\WOW6432Node\\Microsoft\\Windows\\CurrentVersion\\Run", true))
{
key.SetValue("My ApplicationStartUpDemo", "\"" + System.Reflection.Assembly.GetExecutingAssembly().Location + "\"");
}
}
public static void AddApplicationToAllUserStartup()
{
using ( key = Registry.LocalMachine.OpenSubKey("SOFTWARE\\WOW6432Node\\Microsoft\\Windows\\CurrentVersion\\Run", true))
{
key.SetValue("My ApplicationStartUpDemo", "\"" + System.Reflection.Assembly.GetExecutingAssembly().Location + "\"");
}
}
public static void RemoveApplicationFromCurrentUserStartup()
{
using (key = Registry.CurrentUser.OpenSubKey("SOFTWARE\\WOW6432Node\\Windows\\CurrentVersion\\Run", true))
{
key.DeleteValue("My ApplicationStartUpDemo", false);
}
}
public static void RemoveApplicationFromAllUserStartup()
{
using (key = Registry.LocalMachine.OpenSubKey("SOFTWARE\\WOW6432Node\\Microsoft\\Windows\\CurrentVersion\\Run", true))
{
key.DeleteValue("My ApplicationStartUpDemo", false);
}
}
public static bool IsUserAdministrator()
{
//bool value to hold our return value
bool isAdmin;
try
{
//get the currently logged in user
WindowsIdentity user = WindowsIdentity.GetCurrent();
WindowsPrincipal principal = new WindowsPrincipal(user);
isAdmin = principal.IsInRole(WindowsBuiltInRole.Administrator);
}
catch (UnauthorizedAccessException ex)
{
isAdmin = false;
}
catch (Exception ex)
{
isAdmin = false;
}
return isAdmin;
}
}