Python Beautifulsoup(bs4)findAll未找到所有元素

时间:2019-03-21 05:49:09

标签: python web-scraping beautifulsoup

我最终从代码中的URL尝试从页面中收集所有玩家名称。但是,当我使用.findAll来获取所有列表元素时,我还没有成功。请告知。

from urllib.request import urlopen as uReq
from bs4 import BeautifulSoup as soup

players_url = 'https://stats.nba.com/players/list/?Historic=Y'

# Opening up the Connection and grabbing the page
uClient = uReq(players_url)
page_html = uClient.read()

players_soup = soup(page_html, "html.parser")

# Taking all of the elements from the unordered lists that contains all of the players.

list_elements = players_soup.findAll('li', {'class': 'players-list__name'})

3 个答案:

答案 0 :(得分:3)

@Oluwafemi Sule所建议,最好将seleniumBS一起使用:

from bs4 import BeautifulSoup
from selenium import webdriver

driver = webdriver.Firefox()
driver.get('https://stats.nba.com/players/list/?Historic=Y')
soup = BeautifulSoup(driver.page_source, 'lxml')
for div in soup.findAll('li', {'class': 'players-list__name'}):
    print(div.find('a').contents[0])

输出:

Abdelnaby, Alaa
Abdul-Aziz, Zaid
Abdul-Jabbar, Kareem
Abdul-Rauf, Mahmoud
Abdul-Wahad, Tariq

答案 1 :(得分:1)

您可以通过直接从提供名称的js脚本中直接提取请求来完成此操作。

import requests
import json

r = requests.get('https://stats.nba.com/js/data/ptsd/stats_ptsd.js')
s = r.text.replace('var stats_ptsd = ','').replace('};','}')
data = json.loads(s)['data']['players']
players = [item[1] for item in data]
print(players)

答案 2 :(得分:0)

如评论中的@Oluwafemi Sule所述):

  

页面中生成的播放器列表是使用javascript完成的。​​

我建议您不要使用Selenium,而是由非常受欢迎的requests-html的作者创建的此软件包requests。它在后台使用Chromium渲染JavaScript内容。

from requests_html import HTMLSession

session = HTMLSession()
r = session.get('https://stats.nba.com/players/list/?Historic=Y')
r.html.render()
for anchor in r.html.find('.players-list__name > a'):
    print(anchor.text)

输出:

Abdelnaby, Alaa
Abdul-Aziz, Zaid
Abdul-Jabbar, Kareem
Abdul-Rauf, Mahmoud
Abdul-Wahad, Tariq
...