Question

所以这是数组：

let arrayToMatch = ["!", "?", ".", ","];

let string  = "Something!?"; // true
let string2 = "else!"; // false
let string3 = "yes!!"; // true

// if (string has > 2 elemets from arrayToMatch) { do something }

我想检查一下这些字符串是否至少包含来自上面数组的2个元素。因此，第一个字符串将匹配，但第二个字符串将不匹配。

编辑：

我不好，如果string =“ !!”，我也希望它匹配例如

Answer 1

您可以使用reduce进行计数：

let arrayToMatch = ["!", "?", ".", ","];

let string1 = "Something!?";
let string2 = "Other..";
let string3 = "else!";
let string4 = "nothing";

function hasAtLeastXElements(toMatch, str, count = 2) {
    return toMatch.reduce((acc, curr) => 
        str.includes(curr) 
            ? acc + str.split('').filter(x => x === curr).length 
            : acc, 
    0) >= count;
}

console.log(hasAtLeastXElements(arrayToMatch, string1)); // true
console.log(hasAtLeastXElements(arrayToMatch, string2)); // true
console.log(hasAtLeastXElements(arrayToMatch, string3)); // false
console.log(hasAtLeastXElements(arrayToMatch, string4)); // false

编辑：包括重复项。

Answer 2

尝试使用此代码检查重复项

    let string  = "Something!?";
    let string2 = "else!";

    function matchCharacter(string) {
     let arrayToMatch = ["!", "?", ".", ","];
      var duplicate = arrayToMatch.filter(function(atm) {
      if(string.indexOf(atm) != -1) {
         return atm;
        }
     });
    return (duplicate.length >1)?'Duplicate':'not-duplicate';
}


 console.log(matchCharacter(string));

检查字符串中是否至少有2个数组元素

2 个答案: