Question

我在mysql中使用。我创建了表“ Sikcness”，并添加了一条记录：

+--------+---------+---------+-------------+--------+----------+
| Id_SICK|ID_WORKER| BEGIN_DATE          | END_DATE            |
+--------+---------+---------+----------+------------+---------+
| 1      |   1     |2019-03-18 07:00:00  |2019-03-20 15:00:00  |  
+--------+---------+--------+------------+----------+----------+

然后我想通过以下命令对时间进行汇总（“结束日期”列与“开始日期”列之间的时间差）：

SELECT SEC_TO_TIME(SUM(TIME_TO_SEC(Sickness.END_DATE) - TIME_TO_SEC(Sickness.BEGIN_DATE))) AS 'SICKNESS TIME' FROM Sickness WHERE ID_WORKER = 1

但是我只有那个结果（不正确）：

SICKNESS TIME
08:00:00

该命令应该这样计数：

+---------+-------------+--------+----------+
| BEGIN_DATE          | END_DATE            |
+---------+----------+------------+---------+
|2019-03-18 07:00:00  |2019-03-18 15:00:00  |  
+--------+------------+----------+----------+  
|2019-03-19 07:00:00  |2019-03-19 15:00:00  |  
+--------+------------+----------+----------+  
|2019-03-20 07:00:00  |2019-03-20 15:00:00  |  
+--------+------------+----------+----------+

那将是正确的：

SICKNESS TIME
24:00:00

我应该写什么样的mysql查询？有任何想法吗？问候。

Answer 1

小时数差异应乘以天数差异：

mysql> SELECT SEC_TO_TIME(SUM((DATEDIFF(end_date, begin_date) + 1) * (TIME_TO_SEC(END_DATE) - TIME_TO_SEC(BEGIN_DATE)))) AS 'SICKNESS TIME' FROM Sickness WHERE ID_WORKER = 1;
+---------------+
| SICKNESS TIME |
+---------------+
| 24:00:00      |
+---------------+
1 row in set (0.00 sec)

另一个使用TIME_FORMAT的查询：

mysql> select time_format(SUM((datediff(end_date, begin_date) + 1) * (time(end_date) - time(begin_date))), '%H:%i:%s') as 'SICKNESS TIME' from Sickness where id_worker = 1;
+---------------+
| SICKNESS TIME |
+---------------+
| 24:00:00      |
+---------------+
1 row in set (0.00 sec)

您可以在SQL Fiddle上尝试此查询

Answer 2

因此，您需要这样计算：

生病第一天的小时数
生病最后一天的小时数
患病天数乘以8（即工作时间）

完成后，您需要将它们加起来以获得结果，例如

SELECT
TIMESTAMPDIFF(HOUR, begin_date, CONCAT(DATE(begin_date), ' 15:00:00')) +
(TIMESTAMPDIFF(DAY, begin_date, end_date) - 1) * 8 +
TIMESTAMPDIFF(HOUR, CONCAT(DATE(end_date), ' 07:00:00'), end_date) AS time 
FROM test
WHERE worker = 1;

这是 SQL Fiddle 。

如何总结日期时间（end_date和begin_date之间的差异）-MySQL

2 个答案: