我需要使用Javascript从我的Web应用程序将视频上传到youtube。我尝试过两种方式:使用其官方API和使用CORS。他们都没有工作。
解决方案1:使用其API
uploadVideo(infos: any, file: File) {
const params: any = {
part: 'id,snippet,status',
media: {
body: null
},
resource: {
snippet: {
title: infos.title
},
status: {}
},
fileSize: file.size
};
const fileReader = new FileReader();
const optSnippetParams = ['description', 'categoryId', 'defaultLanguage'];
const optStatusParams = ['publishAt', 'privacyStatus', 'license', 'publicStatsViewable'];
for (const i of optSnippetParams) {
if (infos[i]) {
params.resource.snippet[i] = infos[i];
}
}
for (const i of optStatusParams) {
if (infos[i]) {
params.resource.status[i] = infos[i];
}
}
if (infos.tags) {
params.resource.snippet.tags = infos.tags;
}
fileReader.onloadend = (e: ProgressEvent) => {
params.media.body = fileReader.result;
gapi.client.youtube.videos.insert(params).then((res: any) => {
console.log(res);
});
};
fileReader.readAsArrayBuffer(file);
}
此解决方案无效,出现以下错误:
{
"domain": "youtube.video",
"location": "body",
"locationType": "other",
"message": "The request does not include the video content.",
"reason": "mediaBodyRequired"
}
视频内容是在请求正文中实际设置的位置。
解决方案2:使用CORS(我从this file和this file中包含的示例中汲取了灵感)
uploadVideo(token: string, infos: any, file: File) {
const body: any = {
snippet: {
title: infos.title
},
status: {}
};
const optSnippetParams = ['description', 'categoryId', 'defaultLanguage'];
const optStatusParams = ['publishAt', 'privacyStatus', 'license', 'publicStatsViewable'];
for (const i of optSnippetParams) {
if (infos[i]) {
body.snippet[i] = infos[i];
}
}
for (const i of optStatusParams) {
if (infos[i]) {
body.status[i] = infos[i];
}
}
if (infos.tags) {
body.snippet.tags = infos.tags;
}
const xhr = new XMLHttpRequest();
xhr.open('POST', 'https://www.googleapis.com/upload/youtube/v3/videos?part=id,snippet,status', true);
xhr.setRequestHeader('Authorization', 'Bearer ' + token);
/**
* This should works, but doesn't. Error:
* {
* domain: "global",
* message: "Media type 'application/json' is not supported. Valid media types: [video/*, application/octet-stream]"
* reason: "badContent"
* }
*/
// xhr.setRequestHeader('Content-Type', 'application/json');
/** This works */
xhr.setRequestHeader('Content-Type', file.type);
/** This works */
// xhr.setRequestHeader('Content-Type', 'application/octet-stream');
xhr.setRequestHeader('X-Upload-Content-Length', String(file.size));
xhr.setRequestHeader('X-Upload-Content-Type', file.type);
xhr.onload = (e: any) => {
/** location = null */
const location = e.target.getResponseHeader('Location');
/** location is needed to continue upload ... */
};
xhr.onerror = (e: any) => {
console.log('Error:');
console.log(e);
};
xhr.send(JSON.stringify(body));
}
此代码中的第一件事是将'Content-Type'
设置为'application/json'
无效。我有以下错误:
{
domain: "global",
message: "Media type 'application/json' is not supported. Valid media types: [video/*, application/octet-stream]"
reason: "badContent"
}
但是,这就是第131行上的here,因此我选择使用有效的文件类型。
第二件事是,在PUT
请求成功上传后,我需要执行一个POST
请求。为此,我需要使用POST
请求'Location'
标头。但是,当我尝试获取它时,结果总是会有null
。所以我无法继续任何事情。
解决此问题的方法是什么?