在我的SQL 2005 DB中,我有一个表,其值存储为ID,并与其他表有关系。所以在我的 MyDBO.warranty 表中,我存储的是product_id而不是product_name,以节省空间。 product_name存储在 MyDBO.products 中。
当市场营销部门提取人口统计信息时,查询会从相关表中为每个ID选择相应的名称(为简洁起见,将其缩减):
SELECT w1.warranty_id AS "No.",
w1.created AS "Register Date"
w1.full_name AS "Name",
w1.purchase_date AS "Purchased",
(
SELECT p1.product_name
FROM WarrDBO.products p1 WITH(NOLOCK)
WHERE p1.product_id = i1.product_id
) AS "Product Purchased",
i1.accessories
FROM WarrDBO.warranty w1
LEFT OUTER JOIN WarrDBO.warranty_info i1
ON i1.warranty_id = w1.warranty_id
ORDER BY w1.warranty_id ASC
现在,我的问题是warranty_info表上的“附件”列存储了几个值:
No. Register Date Name Purchased Accessories
---------------------------------------------------------------------
1500 1/1/2008 Smith, John Some Product 5,7,9
1501 1/1/2008 Hancock, John Another 2,3
1502 1/1/2008 Brown, James And Another 2,9
我需要使用“附件”执行与“产品”类似的操作,并从 MyDBO.accessories 表中提取 accessory_name 使用 accessory_id 。我不知道从哪里开始,因为首先我需要提取ID然后以某种方式将多个值连接成一个字符串。所以每一行都有“accessoryname1,accessoryname2,accessoryname3”:
No. Register Date Name Purchased Accessories
---------------------------------------------------------------------
1500 1/1/2008 Smith, John Some Product Case,Bag,Padding
1501 1/1/2008 Hancock, John Another Wrap,Label
1502 1/1/2008 Brown, James And Another Wrap,Padding
我该怎么做?
编辑>>发布我的最终代码:
我创建了这个函数:
CREATE FUNCTION SQL_GTOInc.Split
(
@delimited varchar(50),
@delimiter varchar(1)
) RETURNS @t TABLE
(
-- Id column can be commented out, not required for sql splitting string
id INT identity(1,1), -- I use this column for numbering splitted parts
val INT
)
AS
BEGIN
declare @xml xml
set @xml = N'<root><r>' + replace(@delimited,@delimiter,'</r><r>') + '</r></root>'
insert into @t(val)
select
r.value('.','varchar(5)') as item
from @xml.nodes('//root/r') as records(r)
RETURN
END
并相应地更新了我的代码:
SELECT w1.warranty_id,
i1.accessories,
(
CASE
WHEN i1.accessories <> '' AND i1.accessories <> 'NULL' AND LEN(i1.accessories) > 0 THEN
STUFF(
(
SELECT ', ' + a1.accessory
FROM MyDBO.accessories a1
INNER JOIN MyDBO.Split(i1.accessories, ',') a2
ON a1.accessory_id = a2.val
FOR XML PATH('')
), 1, 1, ''
)
ELSE ''
END
) AS "Accessories"
FROM MyDBO.warranty w1
LEFT OUTER JOIN MyDBO.warranty_info i1
ON i1.warranty_id = w1.warranty_id
答案 0 :(得分:5)
您可以编写一个表值函数,只需将逗号分隔的字符串拆分为XML并将XML节点转换为行。
请参阅: http://www.kodyaz.com/articles//t-sql-convert-split-delimeted-string-as-rows-using-xml.aspx
通过函数调用的结果加入附件,并将结果填充回逗号分隔的名称列表。
未经测试的代码:
SELECT w1.warranty_id AS "No.",
w1.created AS "Register Date"
w1.full_name AS "Name",
w1.purchase_date AS "Purchased",
(
SELECT p1.product_name
FROM WarrDBO.products p1 WITH(NOLOCK)
WHERE p1.product_id = i1.product_id
) AS "Product Purchased",
STUFF(
(
SELECT
', ' + a.name
FROM [table-valued-function](i1.accessories) acc_list
INNER JOIN accessories a ON acc_list.id = a.id
FOR XML PATH('')
), 1, 1, ''
) AS [accessories]
FROM WarrDBO.warranty w1
LEFT OUTER JOIN WarrDBO.warranty_info i1
ON i1.warranty_id = w1.warranty_id
ORDER BY w1.warranty_id ASC
答案 1 :(得分:3)
与您的问题无关。只需注意您也可以编写原始查询,将子查询移动到连接,如下:
SELECT w1.warranty_id AS "No.",
w1.created AS "Register Date"
w1.full_name AS "Name",
w1.purchase_date AS "Purchased",
p1.product_name AS "Product Purchased",
i1.accessories
FROM WarrDBO.warranty w1
INNER JOIN WarrDBO.products p1
ON p1.product_id = i1.product_id
LEFT OUTER JOIN WarrDBO.warranty_info i1
ON i1.warranty_id = w1.warranty_id
ORDER BY w1.warranty_id ASC
答案 2 :(得分:1)
您只需使用SQL Server的FOR XML功能轻松捕捉字符串:
链接博客帖子中的示例:
SELECT
STUFF(
(
SELECT
' ' + Description
FROM dbo.Brands
FOR XML PATH('')
), 1, 1, ''
) As concatenated_string
要解析已经存储为逗号分隔的字段,您必须编写一个解析该字段的UDF并返回一个表,然后该表可以与WHERE子句中的IN谓词一起使用。查看here for starters和here。
答案 3 :(得分:0)
它似乎是连接聚合函数的工作。 在SQL中,它可以使用CLR
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