考虑一个自定义类型,该类型用于对持续时间的特定实例进行乘除运算:
#include <chrono>
#include <iostream>
class Foo {};
using Duration = std::chrono::seconds;
inline Duration operator*(Duration d, Foo) {
std::cout << "multiplying some time with Foo\n";
return d;
}
inline Duration operator/(Duration d, Foo) {
std::cout << "dividing some time by Foo\n";
return d;
}
int main() {
Duration d;
Foo f;
d * f;
d / f;
}
此代码使用gcc编译时不会发出警告,但使用clang(wandbox)时失败
In file included from prog.cc:1:
/opt/wandbox/clang-7.0.0/include/c++/v1/chrono:1259:81: error: no type named 'type' in 'std::__1::common_type<long long, Foo>'
typename common_type<typename _Duration::rep, _Rep2>::type>::value>
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~^~~~
/opt/wandbox/clang-7.0.0/include/c++/v1/chrono:1272:7: note: in instantiation of default argument for '__duration_divide_imp<std::__1::chrono::duration<long long, std::__1::ratio<1, 1> >, Foo>' required here
: __duration_divide_imp<duration<_Rep1, _Period>, _Rep2>
^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
/opt/wandbox/clang-7.0.0/include/c++/v1/chrono:1279:10: note: in instantiation of template class 'std::__1::chrono::__duration_divide_result<std::__1::chrono::duration<long long, std::__1::ratio<1, 1> >, Foo, false>' requested here
typename __duration_divide_result<duration<_Rep1, _Period>, _Rep2>::type
^
prog.cc:22:7: note: while substituting deduced template arguments into function template 'operator/' [with _Rep1 = long long, _Period = std::__1::ratio<1, 1>, _Rep2 = Foo]
d / f;
请注意,operator*
在两种编译器中都可以正常工作。
使用在类作用域类型中定义的friend方法,实际的代码更加复杂,该方法对持续时间执行溢出安全的整数运算,但显示出完全相同的症状。
问题看起来类似于:User-defined overloaded operator * with std::chrono::duration,但这是不同的运算符和编译器。
答案 0 :(得分:9)
在我看来,这似乎是一个libc ++错误(也是我写的一个错误)。这是一个经过严格测试的修复程序:
BQUEUE::~BQUEUE() {
if ( front )
{
bqnode *current = front;
while (current->next != front)
Dequeue();
}
}