我正在尝试在子图中绘制数据帧不同列的直方图。
plt_count = 1
for i = names(abalone)[2:end]
p[plt_count]=histogram(abalone[:,i])
plt_count += 1
end
plot(p, layout=(3,3), legend=false)
这是我尝试过的。但是我无法为数组p提出正确的定义。如何定义p？
代码的改进也将有所帮助。
答案 0 :(得分：1)
如果您不关心类型稳定性，可以创建public abstract class Square {
private String name;
private boolean isAvailable;
private Player owner;
//getters and setters
}
public class Property extends Square{
private String colour;
private int buyHouset;
private int rent1House;
private int rent2House;
private int rent3House;
private int rentHotel;
private int numHouses;
private int rent;
private int price;
//getters and setters
}
public static void takeTurn(Player player, Dice die, ArrayList<Square> board) {
System.out.println(player.getGamertag() + "'s turn");
//get value from roll of die
int move = askToRoll();
String gamertag = player.getGamertag();
//if player does not quit continue with turn
if(move > 0) {
//get player current position and add roll of die
int newSpaceIndex = player.getPosition() + move;
//if players new position exceeds the array of squares, return to 0 index and add remainder
//add credits for passing Go
//else update position
if (newSpaceIndex > 11) {
player.setPosition(newSpaceIndex - 12);
Go.passGoAction(player);
}else {
player.setPosition(newSpaceIndex);
}
if(player.getPosition() == 1) {
Square newPosition = board.get(player.getPosition());
System.out.println(gamertag + " new position " + newPosition.getName());
}else if(player.getPosition() == 6) {
FreeParking.freeParkingAction();
} else {
Square newPosition = board.get(player.getPosition());
System.out.println("____________________");
System.out.println("Land on " + newPosition.getName());
if(newPosition.getOwner() != null) {
Player owner = newPosition.getOwner();
/* *****THIS IS WHERE THE ERROR IS STEMING FROM*****
*THE newPosition.getRent() method can not be accessed as newPosition
*is defines as Square
*/
System.out.println(owner.getGamertag() + " demands you pay " + newPosition.getRent() + " credits!");
}else {
System.out.println("What would you like to do now? ...\n"
+ "1. Buy property\n"
+ "2. End turn");
int input = in.nextInt();
boolean valid = false;
do {
switch(input) {
case 1:
System.out.println("You now own controlling stock of " + newPosition.getName());
player.setOwnsProperty(newPosition);
newPosition.setOwner(player);
valid = true;
break;
case 2:
System.out.println("Ending turn");
valid=true;
break;
default:
System.out.println("Invalid input, please select one of the options 1-2");
valid = false;
break;
}
}while(!valid);
}
}
}
System.out.println("END TURN: " + player);
System.out.println();
}
类型数组。
Any如果要专门创建ps = Array{Any}(nothing, 3)
ps[1] = plot([2,3,4])
ps[2] = plot([1,5])
ps[3] = plot([10,5,1,0])
@show typeof(ps)
plot(ps..., layout=(3,1))
类型的数组，一种方法是使用虚拟图初始化数组，然后再替换。
Plot