我正在尝试将文件从一个SpringBoot应用程序发布到另一个SpringBoot应用程序。 我要达到的目标看起来像
@PostMapping(
value = "/upload",
consumes = MULTIPART_FORM_DATA_VALUE)
public ResponseEntity<ArmResponse<JobData>> uploadInvoices(@RequestParam("file") MultipartFile interestingStuff) {
String incomingFilename = interestingStuff.getName();
String originalFilename = interestingStuff.getOriginalFilename();
String contentType = interestingStuff.getContentType();
// do interesting stuff here
return ok(successfulResponse(new JobData()));
}
执行对thios端点的POST请求的应用程序中的代码如下
public void loadInvoices(MultipartFile invoices) throws IOException {
File invoicesFile = new File(invoices.getOriginalFilename());
invoices.transferTo(invoicesFile);
LinkedMultiValueMap<String, Object> parts = new LinkedMultiValueMap<>();
parts.add("file", invoicesFile);
HttpHeaders httpHeaders = new HttpHeaders();
httpHeaders.setContentType(MediaType.MULTIPART_FORM_DATA);
HttpEntity<LinkedMultiValueMap<String, Object>> httpEntity = new HttpEntity<>(parts, httpHeaders);
String url = String.format("%s/rest/inbound/invoices/upload", baseUrl);
final List<HttpMessageConverter<?>> messageConverters = new ArrayList<>();
messageConverters.add(new ByteArrayHttpMessageConverter());
messageConverters.add(new ResourceHttpMessageConverter());
messageConverters.add(new AllEncompassingFormHttpMessageConverter());
messageConverters.add(new FormHttpMessageConverter());
messageConverters.add(new SourceHttpMessageConverter<Source>());
RestTemplate template = new RestTemplate(messageConverters);
template.exchange(
url,
HttpMethod.POST,
httpEntity,
new ParameterizedTypeReference<ArmResponse<JobData>>() {
});
}
如果我使用邮递员以表格形式发布文件-它可以工作 来自邮递员的请求中的内容类型标头看起来像
content-type:"multipart/form-data; boundary=--------------------------286899320410555838190774"
RestTemplate执行POST时,出现以下错误。
com.fasterxml.jackson.databind.exc.MismatchedInputException:由于[Source:(String)“”;行:1,列:0]
我怀疑请求中发送的内容类型标头是错误的。 有谁知道如何正确设置MULTIPART_FORM_DATA的内容类型标头?
答案 0 :(得分:0)
您为什么需要messageConverters?只需使用本教程中的代码即可:https://www.baeldung.com/spring-rest-template-multipart-upload
RestTemplate restTemplate = new RestTemplate();
ResponseEntity<String> response = restTemplate
.postForEntity(url , httpEntity, String.class);
答案 1 :(得分:0)
与往常一样,该解决方案非常简单。只需在multipartFile上调用getResource()。
public void loadInvoices(MultipartFile invoices) throws IOException {
Resource invoicesResource = invoices.getResource();
LinkedMultiValueMap<String, Object> parts = new LinkedMultiValueMap<>();
parts.add("file", invoicesResource);
HttpHeaders httpHeaders = new HttpHeaders();
httpHeaders.setContentType(MediaType.MULTIPART_FORM_DATA);
HttpEntity<LinkedMultiValueMap<String, Object>> httpEntity = new HttpEntity<>(parts, httpHeaders);
restTemplate.postForEntity("my/url", httpEntity, SommeClass.class);
}
答案 2 :(得分:0)
Kotlin 中稍微漂亮的解决方案:
@Test
fun testMultipartUpload() {
val bytes = ByteArray(10240) // Get your bytes however you like.
val resource = object : ByteArrayResource(bytes) {
override fun getFilename() = "xyzzy.jpg"
}
val request = RequestEntity.post("/foobar")
.contentType(MediaType.MULTIPART_FORM_DATA)
.body(LinkedMultiValueMap<String, Any>().apply { add("data", resource) })
val result = testRestTemplate.exchange(request, FooBar::class.java)
Assertions.assertTrue(result.statusCode.is2xxSuccessful)
}