Question

我有一个列表，可以将其转换为FormArray以生成html中的按钮列表。我想按名称过滤汽车

CarComponent.html

  <input #searchBox id="search-box" (input)="search(searchBox.value)" />

<form [formGroup]="form" *ngIf="showCars">
              <input type="button" class ="btn"  formArrayName="carsList" *ngFor="let car of carsList$ | async; let i = index" value="{{carsList[i].name}}" >
        </form>

CarComponent.ts

 carsList$: Observable<Car[]>;
  private searchTerms = new Subject<string>();
  search(term: string): void {
    this.searchTerms.next(term);
  }

constructor(private formBuilder:FormBuilder,...)
{
  this.form = this.formBuilder.group({
      carsList: new FormArray([])
    });

this.addButtons();

}

 ngOnInit() {
    this.spinner.show(); 
    this.carsList$ = this.searchTerms.pipe(
      debounceTime(300),
      distinctUntilChanged(),
      switchMap((term:string)=> 
      this.carsList ??? // Is this correct ?? What do I put here ?
    )




  }

  private addButtons() {

      this.carsList.map((o,i)=>{
        const control = new FormControl;
        (this.form.controls.carsList as FormArray).push(control);
      })
    }

export const CarsList: Car[] = [
  { name: 'Mercedes' },
  { name: 'BMW' },
  { name: 'Porsche' },
  { name: 'Cadillac' }
]

因此，我想知道如何正确执行过滤，而出于性能原因不使用管道。

Answer 1

您可以使用数组filter和数组includes来过滤FormArray或Array中的值。

const CarsList = [
  { name: 'Mercedes' },
  { name: 'BMW' },
  { name: 'Porsche' },
  { name: 'Cadillac' }
];
const result = CarsList.filter(s => s.name.includes('Mercedes'));

console.log(result);

在Angular中过滤表单数组

1 个答案: