Question

我对sql还是很陌生，不知道如何透视表，该表可能会导致来自分类数据列的二进制数据。

这是我当前的表格：

+---------+------------------+--------------------+----------------+
| User ID | Cell Phone Brand | Purchased Platform | Recorded Usage |
+---------+------------------+--------------------+----------------+
|    1001 | Apple            | Retail             |              4 |
|    1001 | Samsung          | Online             |              4 |
|    1002 | Samsung          | Retail             |              5 |
|    1003 | Google           | Online             |              3 |
|    1003 | LG               | Online             |              3 |
|    1004 | LG               | Online             |              6 |
|    1005 | Apple            | Online             |              3 |
|    1006 | Google           | Retail             |              5 |
|    1007 | Goohle           | Online             |              3 |
|    1008 | Samsung          | Retail             |              4 |
|    1009 | LG               | Retail             |              4 |
|    1009 | Apple            | Retail             |              3 |
|    1010 | Apple            | Retail             |              6 |
+---------+------------------+--------------------+----------------+

我希望通过汇总Recorded Usage和设备的二进制数据获得以下结果：

+---------+--------------------+----------------+-------+---------+--------+----+
| User ID | Purchased Platform | Recorded Usage | Apple | Samsung | Google | LG |
+---------+--------------------+----------------+-------+---------+--------+----+
|    1001 | Retail             |              4 |     1 |       0 |      0 |  0 |
|    1001 | Online             |              4 |     0 |       1 |      0 |  0 |
|    1002 | Retail             |              5 |     0 |       1 |      0 |  0 |
|    1003 | Online             |              3 |     0 |       0 |      1 |  0 |
|    1003 | Online             |              3 |     0 |       0 |      0 |  1 |
|    1004 | Online             |              6 |     0 |       0 |      0 |  1 |
|    1005 | Online             |              3 |     1 |       0 |      0 |  0 |
|    1006 | Retail             |              5 |     0 |       0 |      1 |  0 |
|    1007 | Online             |              3 |     0 |       0 |      1 |  0 |
|    1008 | Retail             |              4 |     0 |       1 |      0 |  0 |
|    1009 | Retail             |              4 |     0 |       0 |      0 |  1 |
|    1009 | Retail             |              3 |     1 |       0 |      0 |  0 |
|    1010 | Retail             |              6 |     1 |       0 |      0 |  0 |
+---------+--------------------+----------------+-------+---------+--------+----+

Answer 1

您可以使用case when条语句：

declare @tmp table (UserID int, CellPhoneBrand varchar(10),    PurchasedPlatform varchar(10), RecordedUsage int)

insert into @tmp
values
 (1001,'Apple'  ,'Retail', 4)
,(1001,'Samsung','Online', 4)
,(1002,'Samsung','Retail', 5)
,(1003,'Google' ,'Online', 3)
,(1003,'LG'     ,'Online', 3)
,(1004,'LG'     ,'Online', 6)
,(1005,'Apple'  ,'Online', 3)
,(1006,'Google' ,'Retail', 5)
,(1007,'Goohle' ,'Online', 3)
,(1008,'Samsung','Retail', 4)
,(1009,'LG'     ,'Retail', 4)
,(1009,'Apple'  ,'Retail', 3)
,(1010,'Apple'  ,'Retail', 6)

select UserID, PurchasedPlatform, RecordedUsage
,case when CellPhoneBrand ='Apple' then 1 else 0 end as Apple
,case when CellPhoneBrand ='Samsung' then 1 else 0 end as Samsung
,case when CellPhoneBrand ='Google' then 1 else 0 end as Google
,case when CellPhoneBrand ='LG' then 1 else 0 end as LG


from @tmp

结果：

Answer 2

这是您在预期结果中追求的结果。就像我在评论中提到的那样，我很可能期望这里有一个汇总枢纽：

WITH VTE AS(
    SELECT *
    FROM (VALUES(1001,'Apple  ','Retail',4),
                (1001,'Samsung','Online',4),
                (1002,'Samsung','Retail',5),
                (1003,'Google ','Online',3),
                (1003,'LG     ','Online',3),
                (1004,'LG     ','Online',6),
                (1005,'Apple  ','Online',3),
                (1006,'Google ','Retail',5),
                (1007,'Goohle ','Online',3),
                (1008,'Samsung','Retail',4),
                (1009,'LG     ','Retail',4),
                (1009,'Apple  ','Retail',3),
                (1010,'Apple  ','Retail',6)) V(ID, Brand, Platform, Usage))
SELECT ID,
       Platform,
       Usage,
       CASE WHEN Brand = 'Apple' THEN 1 ELSE 0 END AS Apple,
       CASE WHEN Brand = 'Samsung' THEN 1 ELSE 0 END AS Samsung,
       CASE WHEN Brand = 'Google' THEN 1 ELSE 0 END AS Google,
       CASE WHEN Brand = 'LG' THEN 1 ELSE 0 END AS LG
FROM VTE;

Answer 3

由于您在描述中使用了单词枢轴。这是一个解决方案，展示了如何使用PIVOT语句在sqlserver中透视数据

declare  @temp TABLE
(
  [UserID] varchar(50), 
  [CellPhoneBrand] varchar(50), 
  [PurchasedPlatform] varchar(50),
  [RecordedUsage] int
);

INSERT INTO @temp
(
  [UserID], 
  [CellPhoneBrand], 
  [PurchasedPlatform],
  [RecordedUsage]

)
VALUES
(1001,'Apple',        'Retail',        4),
(1001,'Samsung',      'Online',        4),
(1002,'Samsung',      'Retail',        5),
(1003,'Google',       'Online',        3),
(1003,'LG',           'Online',        3),
(1004,'LG',           'Online',        6),
(1005,'Apple',        'Online',        3),
(1006,'Google',       'Retail',        5),
(1007,'Goohle',       'Online',        3),
(1008,'Samsung',      'Retail',        4),
(1009,'LG',           'Retail',        4),
(1009,'Apple',        'Retail',        3),
(1010,'Apple',        'Retail',        6)


select *
from 
(
  select [UserID], [PurchasedPlatform], [RecordedUsage],[CellPhoneBrand]
  from @temp
) src
pivot
(
  count(CellPhoneBrand)
  for [CellPhoneBrand] in ([Apple], [Samsung],[Google],[LG])
) piv;

如何透视表创建二进制数据？

3 个答案: