Question

Imagine a scenario where monthly rent is 100,000 which is payable at the end of each month. A tenant then decides to make a payment 350,000 to cater for the current month and those ahead. How do I distribute this amount since I can obviously see here that this amount caters for 3 months and a half month? Here is what I was trying in PHP but I just can't get the last 50,000 to appear.

$rent       = 100000; // rent amount
$amountPaid = 350000; // amount paid by tenant

$length     = $amountPaid/$rent; // number of months paid for

for ($c = 1; $c <= $length; $c++) 
{
    $foreachMonth = $rent;
    assignRentFunction($c, $foreachMonth);
}

function assignRentFunction($count, $amt)
{
    echo "Month ".$count.': '.$amt."<br>";
}

Answer 1

步骤：

1）使用ceil()函数获得总计月份。

2）将返回4个月。 3个月全额支付，一个月仅支付50000。

3）现在，每个循环将使总租金增加10000。

4）如果超过付款金额，则获得mod为50000

$rent       = 100000; // rent amount
$amountPaid = 350000; // amount paid by tenant
$length     = ceil($amountPaid/$rent); // number of months paid for
$totalRent = 0;
for ($c = 1; $c <= $length; $c++) {
    $totalRent += $rent;
    $foreachMonth = $rent;
    if ($amountPaid < $totalRent) { // Here is the logic, if amount exceeds, use the remaining amount.
        $foreachMonth = $amountPaid % $rent;
    }    
    assignRentFunction($c, $foreachMonth);
}
function assignRentFunction($count, $amt) {
    echo "Month ".$count.': '.$amt."<br>";
}

**Output:**

Month 1: 100000
Month 2: 100000
Month 3: 100000
Month 4: 50000

Answer 2

将循环部分更改为

for ($c = 1; $c <= $length; $c++) { 
  $foreachMonth = $rent;
  assignRentFunction($c, $foreachMonth);
}
$fractionalMonth = $length - intval($length);
if ($fractionalMonth)
  assignRentFunction($c, $foreachMonth * $fractionalMonth);

您的错误是因为您总是将$c加1，所以无法获得上个月的小数部分

Answer 3

您可以像这样解决您的问题，

   View vv((TestQuestion)getActivity()).findViewById(R.id.count_down_strip);
    bbb=vv.findViewById(R.id.finish);

Demo。

Answer 4

由于似乎有很多方法可以切片，所以我想我也应该把帽子戴在戒指上

function makeColor(colorNum, colors){
    if (colors < 1) colors = 1;
    // defaults to one color - avoid divide by zero
    return colorNum * (360 / colors) % 360;
}
// This could be length of your array.
var totalDIVs = 20;
var totalColors = totalDIVs;

for (var i = 0; i < totalDIVs; i++){
    var element = document.createElement('div');
    document.body.appendChild(element);
    var color = "hsl( " + makeColor(i, totalColors) + ", 100%, 50% )";
    element.style.backgroundColor = color;
    element.innerHTML = color;
}

现在是评论版本：

for($c = 1; $c<=ceil($amountPaid/$rent); $c++){
    assignRentFunction($c, $rent - max(($c * $rent - $amountPaid),0));
}

Answer 5

$rent= 100000; // rent amount
$amountPaid= 350000; // amount paid by tenant
$length= $amountPaid/$rent; // number of months paid for
for ($c = 1; $c <= ceil($length); $c++) 
{
    $foreachMonth = 100000;
    if($amountPaid>$rent)
    {
        $rent=$rent;
        $amountPaid=$amountPaid-$rent;
    }
    else
    {
        $rent=$rent-$amountPaid;
    }
    assignRentFunction($c, $rent);
}

function assignRentFunction($count, $amt)
{

    echo "Month ".$count.': '.$amt."<br>";
}

Distribute a payment value through monthly period

5 个答案: