我希望所有URL出现在“ 端点” json下。
我尝试通过将String转换为JSON并随后使用JSON parsar来访问它。但是不能成功。
{
"process":{
"id":"epsswitch/process/create-switch-bdl",
"views":{
"selection":{
"uri":"//scp/sdf/sdf/s/df",
"controller":"scp/switching/createswitchingbdl/controllers/selection"
},
"customers":{
"uri":"//scp/vv/vv/views/Customers",
"controller":"scp/x/vc/controllers/customers"
},
"instructions":{
"uri":"//scp/df/fd/views/Information",
"controller":"scp/switching/fd/controllers/instructions"
},
"confirm":{
"uri":"//scp/switching/createswitchingbdl/views/Confirmation",
"controller":"scp/switching/createswitchingbdl/controllers/confirm"
}
},
"endpoints":{
"data":{
"uri":"/epsswitch/create/data?cc=true&al=true&ac=true"
},
"bank":{
"uri":"/fdd/df/df/v1/bank/df/",
"method":"GET"
}
}
}
答案 0 :(得分:0)
有多种解析JSON字符串的方法。我使用json简单(org.json.simple),java json是其中的一些。以下代码使用后者。它从json字符串中获取所有键,并检索每个键中的所有值。
String sJSONString = "<your json object here>";
JSONObject jsObjects = new JSONObject(sJSONString);
//This is where you get your keys
Iterator<String> keys = jsObjects.keys();
//Use while if you need to poll for each key in JSON string
while(keys.hasNext())
{
String keyN = keys.next();
JSONObject jsoObjN = new JSONObject();
jsoObjN = (JSONObject)jsObjects.get(keyN);
//<Your logic here>
}
答案 1 :(得分:0)
下面的代码可以帮助我实现这一目标。
final JsonNode studentNode = mapper.readTree(sPhone.getProcessJson());
JsonNode process = studentNode.get("process");
JsonNode endpoints = process.get("endpoints");
for (JsonNode jsonNode : endpoints) {
JsonNode uri = jsonNode.get("uri");
}