如何识别HandleErrorAttribute OnException中的javascript fetch()?

时间:2019-03-07 16:40:51

标签: javascript asp.net-mvc error-handling fetch

在asp.net mvc应用程序中,我成功处理了从JavaScript到Controller进行jquery $ .ajax调用时发生的异常。当我从javascript进行javascript fetch()调用时,我想以相同的方式处理错误,但是我不知道如何识别进行了fetch()调用。

我正在使用从HandleErrorAttribute派生的类来处理所有Controller错误。这是通过将以下行添加到global.asax Application_Start来完成的:

GlobalFilters.Filters.Add(new Areas.Insurance.Helpers.MyHandleErrorAttribute());

在MyHandleErrorAttribute中,我重写了OnException方法,以便与常规get或post错误区别对待Ajax错误。如果出现ajax错误,我希望返回一个包含guid的对象并触发javascript中的$ .ajax“ error:”回调。如果有由javascript fetch()调用引起的错误,我希望response.ok返回“ false”并传递回包含错误guid的对象。如果错误不是ajax错误或javascript fetch()错误,我想重定向到我们的自定义错误页面。代码如下:

public override void OnException(ExceptionContext filterContext)
    {
        if (filterContext.Exception == null)
            return;

        //log the error
        Guid guid = MyClass.LogError(filterContext.Exception.GetBaseException());

        if (filterContext.HttpContext.Request.IsAjaxRequest()
            && filterContext.Exception != null)
        {
            //this is an error from a $ajax call.
            //500 is needed so that $ajax "error:" function is hit, instead of "success:"
            filterContext.HttpContext.Response.StatusCode = (int)HttpStatusCode.InternalServerError;

            filterContext.Result = new JsonResult()
            {
                Data = new MyErrorObject()
                {
                    Guid = guid
                }
                ,JsonRequestBehavior = JsonRequestBehavior.AllowGet
                //JsonRequestBehavior.AllowGet prevents following sporadic error: System.InvalidOperationException: This request has been blocked because sensitive information could be disclosed to third party web sites when this is used in a GET request. To allow GET requests, set JsonRequestBehavior to AllowGet.
            };

            //this stops Application_OnError from firing
            filterContext.ExceptionHandled = true;

            //this stops the web site from using the default IIS 500 error. 
            //in addition must set existingResponse="Auto" ("PassThrough also works) in web.config httpErrors element.
            filterContext.HttpContext.Response.TrySkipIisCustomErrors = true;
        }
        else
        {
            //if condition to avoid error "Server cannot set status after HTTP headers have been sent"
            if (!filterContext.HttpContext.Response.IsRequestBeingRedirected)
            {
                filterContext.Result = new RedirectToRouteResult(
                    new System.Web.Routing.RouteValueDictionary
                    {
                    {"action", "Error500" },
                    {"controller", "Error" },
                    { "Guid", guid}
                    });
                filterContext.HttpContext.Response.StatusCode = (int)HttpStatusCode.OK;
                filterContext.ExceptionHandled = true;
            }
        }
    }

我的问题是,使用javascript fetch()进行调用时,“ IsAjaxRequest”返回false,因此未命中第一个“ if”块。相反,我进入“ else”块,该块将Http响应设置为“ OK”,并重定向到我的错误页面,这都不是必需的(当我遇到fetch()错误时,我想返回500响应,当然重定向无效。

如何识别进行了javascript fetch()调用?是否有类似于“ IsAjaxRequest”的内容?

这是javascript提取的样子:

let url = '/myDomain/ThrowException';
    fetch(url)
        .then(function (data) {
          if(data.ok){
            //do something with data
           }
          else{
              handleHttpErrorFunction(data);
          }
        })
        .catch(function (error) {
            handleFetchErrorFunction(error);
        });

这是我要替换为fetch()调用的(成功处理的)jquery ajax调用:

 $.ajax({
        url: '/myDomain/ThrowException',
        type: 'GET',
        success: function (data) {
            //do something with data
        },
        error: function (XMLHttpRequest, ajaxOptions, ex) {
            ajaxerrorhandler(XMLHttpRequest);
        }

1 个答案:

答案 0 :(得分:0)

请参阅From server, how recognize javascript fetch() call was made (asp.net mvc)上相关问题的答案。解决方法是在标头中发送X-Requested-With XMLHttpRequest:

fetch('/MyDomain/MyControllerAction', { headers: { 'X-Requested-With': 'XMLHttpRequest' } })