我有一个像这样的XML文件:
"<?xml version ='1.0' encoding='UFT-8'?>"+
"<CLOSE_TRAILER>"+
"<user>" +
"<id>0600580</id>" +
"<trans_id>7</trans_id>" +
"<host_name>Mnull</host_name>"+
"<session_token>79430831Zahyy</session_token>" +
"<time_stamp>1551736026682</time_stamp>" +
"</user>"+
"<trailer_detail>" +
"<org_id>432</org_id>" +
"<trailer_prefix>XTRA</trailer_prefix>" +
"<system_type>SCAN</system_type>" +
"<truck_mail_flag>false</truck_mail_flag>" +
"<trailer_type_code>T</trailer_type_code>" +
"<in_contingency_flag>false</in_contingency_flag>" +
"<detl_code_svc_type>OVN</detl_code_svc_type>" +
"<catg_code_svc_type></catg_code_svc_type>" +
"<seal_number>12345</seal_number>" +
"<user_id>5155035</user_id>" +
"<trailer_number>24813</trailer_number>" +
"</trailer_detail>"+
"<load_handler>" +
"<employee_id>TEST</employee_id>" +
"<trailer_load_seq>71373839</trailer_load_seq>" +
"<action_code></action_code>" +
"</load_handler>"+
"</CLOSE_TRAILER>";
我想将 trailer_detail 和 load_handler 而不是 user 映射到我为此xml创建的对象中:
@JsonRootName(value = "CLOSE_TRAILER")
public class CloseTrailerXml {
@JsonUnwrapped
Trailer trailer_detail;
@JsonUnwrapped
LoadHandler load_handler;
}
我映射的Trailer类是这样的: @JsonRootName(“ trailer_detail”)
public class Trailer {
private Integer equipmentSeq;
private String createdBy;
private ZonedDateTime createdDt;
private String updatedBy;
private ZonedDateTime updatedDt;
@JsonProperty("trailer_number")
private String trlrNbr;
...更多成员变量
在单元测试用例中,我将上面的xml存储为字符串,并在下面使用此代码将其映射到对象中:
String msgNoNewLineChar = originalScannerMsg.replace("\\n","");
String msgNoCarReturnChar = msgNoNewLineChar.replace("\\r", "");
XmlMapper xmlMapper = new XmlMapper();
xmlMapper.setSerializationInclusion(Include.NON_NULL);
CloseTrailerXml closeTrailerXml= xmlMapper.readValue(originalScannerMsg, CloseTrailerXml.class);
closeTrailerXml 已创建,但所有值均为空。 如果我删除了编码行和CLOSE_TRAILER标签以及用户部分,它的映射就很好。
为什么对象映射器不能与当前用户部分一起使用?