如何映射两个数组以创建对象?

时间:2019-03-06 15:47:48

标签: javascript arrays

我有两个数组,我需要创建类似{x: new Date(2019, 1, 1), y: 0}的对象。数组的结果看起来像这样

dates

Array [
  "2019, 1, 31",
  "2019, 2, 28",
  "2019, 3, 31",
]

monthlyTopUp

Array [
  0,
  50,
  0,
]

现在,第一个数组中的每个索引都需要与第二个数组中的索引匹配。

我尝试过的返回一个数组,里面有其他数组

Array [
  Array [
    "2019, 1, 31",
    0,
  ],
  Array [
    "2019, 2, 28",
    50,
  ],
  Array [
    "2019, 3, 31",
    0,
  ],
]

我这样做的方式:

const array = [dates, monthlyTopUp];
const data = array.reduce(
  (dates, topUp) => topUp.map((v, i) => (dates[i] || []).concat(v)), []
);
console.log(data)

3 个答案:

答案 0 :(得分:2)

您可以这样做:

var arr1 = ["2019, 1, 31",  "2019, 2, 28",  "2019, 3, 31"];
var arr2 = [0, 50, 0];

var result = [];

for(var i = 0; i < arr1.length; i++){
    result.push({'x':arr1[i], 'y':arr2[i]});
}

console.log(result);

答案 1 :(得分:1)

或array.map

var arr1 = ["2019, 1, 31",  "2019, 2, 28",  "2019, 3, 31"];
var arr2 = [0, 50, 0];

var result = arr1.map((v, k) => {return {x:v,y:arr2[k]}})

console.log(result);

https://jsfiddle.net/fgo5wanh/

答案 2 :(得分:1)

您可以使用Array.prototype.reduce

let arr1 = ["2019, 1, 31",  "2019, 2, 28",  "2019, 3, 31"];
let arr2 = [0, 50, 0];

let final=arr1.reduce((acc,value,i)=>{
let tempobj={};

tempobj["x"]=new Date(value.replace(/\s/g, "").replace(/,/g, "-"));
tempobj["y"]=arr2[i];
acc.push(tempobj)
return acc;


},[])

console.log(final)