我有两个数组,我需要创建类似{x: new Date(2019, 1, 1), y: 0}
的对象。数组的结果看起来像这样
dates
Array [
"2019, 1, 31",
"2019, 2, 28",
"2019, 3, 31",
]
monthlyTopUp
Array [
0,
50,
0,
]
现在,第一个数组中的每个索引都需要与第二个数组中的索引匹配。
我尝试过的返回一个数组,里面有其他数组
Array [
Array [
"2019, 1, 31",
0,
],
Array [
"2019, 2, 28",
50,
],
Array [
"2019, 3, 31",
0,
],
]
我这样做的方式:
const array = [dates, monthlyTopUp];
const data = array.reduce(
(dates, topUp) => topUp.map((v, i) => (dates[i] || []).concat(v)), []
);
console.log(data)
答案 0 :(得分:2)
您可以这样做:
var arr1 = ["2019, 1, 31", "2019, 2, 28", "2019, 3, 31"];
var arr2 = [0, 50, 0];
var result = [];
for(var i = 0; i < arr1.length; i++){
result.push({'x':arr1[i], 'y':arr2[i]});
}
console.log(result);
答案 1 :(得分:1)
或array.map
var arr1 = ["2019, 1, 31", "2019, 2, 28", "2019, 3, 31"];
var arr2 = [0, 50, 0];
var result = arr1.map((v, k) => {return {x:v,y:arr2[k]}})
console.log(result);
答案 2 :(得分:1)
您可以使用Array.prototype.reduce
let arr1 = ["2019, 1, 31", "2019, 2, 28", "2019, 3, 31"];
let arr2 = [0, 50, 0];
let final=arr1.reduce((acc,value,i)=>{
let tempobj={};
tempobj["x"]=new Date(value.replace(/\s/g, "").replace(/,/g, "-"));
tempobj["y"]=arr2[i];
acc.push(tempobj)
return acc;
},[])
console.log(final)