我想我的问题很简单,但我无法弄清楚。 翻译:Ja =是/ Nee =否
因此,如果单元格A2说“ Nee”,那么J2中应该有一个句子,否则就什么也不做。 每行的其他所有单元格都一样。
我运行我的代码,它执行if语句。但是它只需要合并到一个单元格中即可。
带有示例显示方式的Excel屏幕快照如下:
代码:
Sub SampleMacro()
' Get the last row
Dim startRow As Long, lastRow As Long
startRow = 2
lastRow = Sheet1.Cells(Sheet1.Rows.Count, 1).End(xlUp).Row
Dim i As Long, Wat As String
Dim j As Long, Waarom As String
Dim sClass As String
Dim tClass As String
' Go through the parameter columns
For i = startRow To lastRow
Wat = Sheet1.Range("A" & i).Value
' Check parameters and classify accordingly
If Wat = "Nee" Then
sClass = " Er wordt in de cookie policy niet uitgelegd wat cookies zijn."
Else
sClass = ""
End If
For j = startRow To lastRow
Waarom = Sheet1.Range("B" & j).Value
If Waarom = "Nee" Then
tClass = " Waarom ze nuttig zijn is hier niet omschreven."
Else
tClass = ""
End If
' Write out the class to columns
Sheet1.Range("J" & i).Value = sClass
Sheet1.Range("K" & j).Value = tClass
Next
Next
End Sub
答案 0 :(得分:0)
您的代码可以简化为:
For i = startRow To lastRow
' Check parameters and classify accordingly
If Sheet1.Range("A" & i).Value = "Nee" Then
Sheet1.Range("J" & i).Value = " Er wordt in de cookie policy niet uitgelegd wat cookies zijn."
End If
' If there's Nee in B column, then append next sentence with new line (Chr(10))
If Sheet1.Range("B" & i).Value = "Nee" Then
Sheet1.Range("J" & i).Value = Sheet1.Range("J" & i).Value & Chr(10) & " Waarom ze nuttig zijn is hier niet omschreven."
End If
Next
答案 1 :(得分:0)
您可以尝试将此公式放在J列中,这样可以避免使用宏
=IF(A2="Nee",IF(B2="Nee"," Er wordt in de cookie policy niet uitgelegd wat cookies zijn." &CHAR(10)& " Waarom ze nuttig zijn is hier niet omschreven."," Er wordt in de cookie policy niet uitgelegd wat cookies zijn."),"")