Question

我必须计算至少有多少个连续的自然数（即正整数，例如1、2、3，...），我们必须乘以至少输入乘积（因此，数字的乘积必须大于或等于输入的数字）。使用循环进行计算。程序应在语句中列出答案。如果输入33，答案是：“要获得至少33，我们需要将前5个自然数相乘。”

Answer 1

尝试：

number_calc = 33

def calculate(number):
  last_number = 1
  prod = 1
  if number == 1:
      pass
  else:
    while prod <= number :
      last_number = last_number + 1
      prod = prod*last_number
  return last_number

answer = calculate(number_calc)
print("To get at least {}, we need to multiply the first {} natural numbers.".format(number_calc,answer))

但是您应该听这些注释并自己尝试一下，这是一个非常基本的代码示例。

Answer 2

尝试以下代码：

x = int(input("Enter a Number"))
count = 1
j = 1
for i in range(1,x):
    count =  count * i
    if count >= x: # Count till your product is greater than or equal to entered number
       j = i
       break # Break here to avoid anymore loop
print ("To get at least {}, we need to multiply the first {} natural numbers.".format(x,j))

Python-计算所需的自然数

2 个答案: