Question

我发现一些Python2代码可以从Excel文件中提取图像。

我有一个非常基本的问题：我应该在哪里指定目标Excel文件的路径？

还是仅对打开的活动Excel文件起作用？

import win32com.client       # Need pywin32 from pip
from PIL import ImageGrab    # Need PIL as well
import os

excel = win32com.client.Dispatch("Excel.Application")
workbook = excel.ActiveWorkbook

wb_folder = workbook.Path
wb_name = workbook.Name
wb_path = os.path.join(wb_folder, wb_name)

#print "Extracting images from %s" % wb_path
print("Extracting images from", wb_path)

image_no = 0

for sheet in workbook.Worksheets:
    for n, shape in enumerate(sheet.Shapes):
        if shape.Name.startswith("Picture"):
            # Some debug output for console
            image_no += 1
            print("---- Image No. %07i ----", image_no)

            # Sequence number the pictures, if there's more than one
            num = "" if n == 0 else "_%03i" % n

            filename = sheet.Name + num + ".jpg"
            file_path = os.path.join (wb_folder, filename)

            #print "Saving as %s" % file_path    # Debug output
            print('Saving as ', file_path)

            shape.Copy() # Copies from Excel to Windows clipboard

            # Use PIL (python imaging library) to save from Windows clipboard
            # to a file
            image = ImageGrab.grabclipboard()
            image.save(file_path,'jpeg')

Answer 1

您可以像这样从现有的Excel文件中抓取图像：

from PIL import ImageGrab
import win32com.client as win32

excel = win32.gencache.EnsureDispatch('Excel.Application')
workbook = excel.Workbooks.Open(r'C:\Users\file.xlsx')

for sheet in workbook.Worksheets:
    for i, shape in enumerate(sheet.Shapes):
        if shape.Name.startswith('Picture'):
            shape.Copy()
            image = ImageGrab.grabclipboard()
            image.save('{}.jpg'.format(i+1), 'jpeg')

Answer 2

文件路径和文件名在以下变量中定义：

wb_folder = workbook.Path
wb_name = workbook.Name
wb_path = os.path.join(wb_folder, wb_name)

在这种情况下，它将在前一行调用活动工作簿：

workbook = excel.ActiveWorkbook

但是从理论上讲，只要您将文件加载到excel模块（Python: Open Excel Workbook using Win32 COM Api）上，就应该能够使用wb_folder和wb_name变量指定路径。

Answer 3

xlsx文件实际上是一个zip文件。您可以直接从xl / media子文件夹获取图像。您可以使用ZipFile类在python中执行此操作。您不需要MS Excel，甚至不需要在Windows中运行！

使用python从Excel工作表中提取图像

3 个答案: