Question

我有一个项目，我在其中处理表单的条件规则。此时，我有两个对象，其中一个是条件，另一个是填写的表单字段，需要根据条件进行检查。

我已经做了两个对象，对我来说，下一个逻辑步骤是if statement，它检查表单对象是否包含所有条件对象的值。（如果我错了，请纠正我）

我将在此处显示两个对象：

let conditions = {
    carrier: "PostNL",
    country: "Deutschland"
}

let ticket_data = {
    carrier: "PostNL",
    client: "testdata",
    comment: "testdata",
    country: "Deutschland",
    postal_code: "testdata",
    service_level: "testdata",
}

如您所见，对象ticket_data包含对象conditions包含的所有数据。在这种情况下，if statement应该返回true。但是，如果其中一个值不存在或不等于conditions对象，则应返回false。

执行此操作的最佳和最简便的方法是什么？

Answer 1

您可以拿起键并检查every的键值。

let conditions = { carrier: "PostNL", country: "DeutschlandTEST" }
let ticket_data = {carrier: "PostNL",client: "testdata",comment: "testdata",country: "Deutschland",postal_code: "testdata",service_level: "testdata",}
  
let checkTrue = Object.keys(conditions).every( e => ticket_data[e] )
let matchValues = Object.keys(conditions).every( e =>conditions[e] === ticket_data[e] )


if(Object.keys(conditions).every( e => ticket_data[e] )){
 console.log(`Yeah it's working`) 
}

console.log(checkTrue, matchValues)

Answer 2

对象键/条目和每一个。每个循环结束，检查是否匹配。如果匹配失败，它将停止循环。

let conditions = {
    carrier: "PostNL",
    country: "Deutschland"
}
let ticket_data = {
    carrier: "PostNL",
    client: "testdata",
    comment: "testdata",
    country: "Deutschland",
    postal_code: "testdata",
    service_level: "testdata",
}

const isMatch = Object.keys(conditions)
  .every(key => 
    conditions[key] === ticket_data[key])
    
console.log(isMatch)

const isMatch2 = Object.entries(conditions)
  .every(([key, value]) => 
    value === ticket_data[key])
    
console.log(isMatch2)

Answer 3

比较两者的Object.keys：

let conditions = {
    carrier: "PostNL",
    country: "Deutschland"
}

let ticket_data = {
    carrier: "PostNL",
    client: "testdata",
    comment: "testdata",
    country: "Deutschland",
    postal_code: "testdata",
    service_level: "testdata",
}

const ticket_data_keys = Object.keys(ticket_data);

const result = Object.keys(conditions).every(key => ticket_data_keys.includes(key));

console.log(result);

Answer 4

我会做这样的事情：

let conditions = {
    carrier: "PostNL",
    country: "Deutschland"
}

let ticket_data = {
    carrier: "PostNL",
    client: "testdata",
    comment: "testdata",
    country: "Deutschland",
    postal_code: "testdata",
    service_level: "testdata",
}

const requiredProps = [
    'carrier', 'client', 'comment', 'country', 'postal_code', 'service_level'
];

const checkIfIsValid = (ticketData) => {
    const keys = Object.keys(ticketData);

    // Check for equality
    const areEquals = (keys.length == requiredProps.length) && keys.every(function(element, index) {
        return element === requiredProps[index]; 
    });

    if (!areEquals) {
        return false;
    }

    if (ticketData.carrier !== conditions.carrier) {
        return false;
    }

    if (ticketData.country !== conditions.country) {
        return false;
    }

    return true;
}

if (checkIfIsValid(ticket_data)) {
    console.log('OK');
} else {
    console.log('ERROR');
}

检查JavaScript对象是否包含其他对象的值

4 个答案: