Question

我有一个列表，我想转换为特定的字典dict_a

输入：

a = ['AAA: key1', 'value1', 'value2', 'AAA: key2', 'value3', 'value4', 'value5', 'AAA: key3', 'value6', 'value7']

预期输出：

dict_a = {'key1': [value1, value2], 'key2': [value3, value4, value5], 'key3': [value6, value7]}

我的尝试：

for elem in a:
    if a.startswith(AAA:):
        d_a = {elem}

Answer 1

这是使用collections.defaultdict的一种方式：

from collections import defaultdict

a = ['AAA: key1', '  value1', '  value2', 'AAA: key2', '  value3', '  value4', '  value5', 'AAA: key3', '  value6', '  value7']

d = defaultdict(list)
for x in a:
    if not x.startswith('AAA'):
        d[c].append(x.strip())
    else:
        c = x.split(': ')[1]

print(d)
# defaultdict(<class 'list'>, {'key1': ['value1', 'value2'], 'key2': ['value3', 'value4', 'value5'], 'key3': ['value6', 'value7']})

Answer 2

我喜欢使用生成器来解决此类问题，将结果累加起来，我们看到下一个结果开始，然后产生我们收集的结果。

def key_val_gen(a):
    key = None
    vals = []
    for item in a:
        if item.startswith('AAA: '):
            if key:
                yield key, vals
            key  = item.split(maxsplit=1)[1]
            vals = []
        else:
            vals.append(item)
    if key:
        yield key, vals

a = ['AAA: key1', 'value1', 'value2', 'AAA: key2', 'value3', 'value4', 'value5', 'AAA: key3', 'value6', 'value7']

print(dict(key_val_gen(a)))
# {'key1': ['value1', 'value2'], 'key2': ['value3', 'value4', 'value5'], 'key3': ['value6', 'value7']}

Answer 3

Dim newFileName as String
' build the filename parmaeter:
newFileName = Left(thisWb.FullName, d - 1) & "- Prelims" & Mid(thisWb.FullName, d)
thisWb.SaveCopyAs Filename:=newFileName
thisWb.Close savechanges:=False

' Open the new workbook:
Dim newWorkbook as Workbook
Set newWorkbook = Workbooks.Open(newFileName)

Answer 4

您还可以使用itertools.groupby将“是键”和“是值”中的项目分组，然后通过在同一迭代器上使用next来组合连续的元素：

>>> from itertools import groupby
>>> groups = (next(g).lstrip("AAA: ") if k else list(g)
...           for k, g in groupby(a, key=lambda x: x.startswith("AAA: ")))
...
>>> {g: next(groups) for g in groups}
{'key1': ['value1', 'value2'],
 'key2': ['value3', 'value4', 'value5'],
 'key3': ['value6', 'value7']}

Python将列表转换为特定字典

4 个答案: