Question

我正在使用c＃ASP.NET 我有一个类似于下面的GridView

ID | Name | Date       | DocID
-----------------------------
 1 | John | 27/02/2019 |  1
 2 | Mary | 20/01/2019 |  2
 3 | Mark | 01/01/2019 |  3
 3 | Mark | 01/01/2019 |  4
 3 | Mark | 01/01/2019 |  5

DocID是指向上载到数据库的文档的链接。

我已经能够将重复的行合并为1，因此我的表当前如下所示

ID | Name | Date       | DocID
-----------------------------
 1 | John | 27/02/2019 |  1
 2 | Mary | 20/01/2019 |  2
 3 | Mark | 01/01/2019 |  3 4 5

除此之外，我现在对所有3个文档都有1个链接，而不是每个文档都有一个链接。

有没有一种方法可以使每个文档都有自己的链接，但仅使用一个LinkButton？或者我缺少某些东西，而链接按钮不是这样做的方法吗？

预先感谢

编辑：这是我针对上下文的一些代码
创建GridView

using (SqlCommand cmd = new SqlCommand("SELECT tblQuote.qID, tblQuote.qInsurer, tblQuote.qDate, tblQuote.qQuote, tblQuote.qTerms, tblQuote.qUser, tblQMethod.qmDesc, " +
                                                "STUFF((SELECT ' ' + CAST(dID AS VARCHAR) FROM tblDocuments WHERE tblDocuments.qID = tblQuote.qID FOR XML PATH('')),1, 0, '') [dID], " +
                                                "STUFF((SELECT ' ' + dName FROM tblDocuments WHERE tblDocuments.qID = tblQuote.qID FOR XML PATH('')),1, 0, '') [dName] " +
                                                "FROM tblQuote INNER JOIN tblQMethod ON tblQuote.qQMethod = tblQMethod.qmID " +
                                                "WHERE tblQuote.rID = " + Session["riskID"], tcf))
        {
            DataTable dt = new DataTable();
            using (SqlDataAdapter da = new SqlDataAdapter(cmd))
            {
                da.Fill(dt);
                gvQuote.DataSource = dt;
                gvQuote.DataBind();
            }
        }

文档链接

protected void lnkDocument_Click(object sender, EventArgs e)
    {
        int dID = int.Parse((sender as LinkButton).CommandArgument);
        byte[] bytes;
        string fileName, contentType;
        using (SqlCommand cmd = new SqlCommand("SELECT * FROM tblDocuments WHERE dID = @dID", tcf))
        {
            cmd.Parameters.AddWithValue("@dID", dID);
            tcf.Open();
            using (SqlDataReader sdr = cmd.ExecuteReader())
            {
                sdr.Read();
                bytes = (byte[])sdr["dDocument"];
                contentType = sdr["dType"].ToString();
                fileName = sdr["dName"].ToString();
            }
            tcf.Close();
        }
        Response.Clear();
        Response.Buffer = true;
        Response.Charset = "";
        Response.Cache.SetCacheability(HttpCacheability.NoCache);
        Response.ContentType = contentType;
        Response.AppendHeader("Content-Disposition", "attachment; filename=" + fileName);
        Response.BinaryWrite(bytes);
        Response.Flush();
        Response.End();
    }

GridView TemplateField

<asp:TemplateField HeaderText="Documents Link">
                    <ItemTemplate>
                        <asp:LinkButton ID="lnkDocument" runat="server" Text='<%# Bind("dID") %>' ToolTip='<%# Bind("dName") %>' CommandArgument='<%# Eval("dID") %>' OnClick="lnkDocument_Click"></asp:LinkButton>
                    </ItemTemplate>
                </asp:TemplateField>

中继器代码 通过在RowDataBound下添加以下代码，我已经能够使链接单独显示，但是现在所有文档都显示在DocID中

if (e.Row.RowType == DataControlRowType.DataRow)
        {
            Repeater rp = (Repeater)e.Row.FindControl("rpDocument");
            using (SqlCommand cmd = new SqlCommand("SELECT dID, dName FROM tblDocuments", tcf))
            {
                DataTable dt = new DataTable();
                using (SqlDataAdapter da = new SqlDataAdapter(cmd))
                {
                    da.Fill(dt);
                    rp.DataSource = dt;
                    rp.DataBind();
                }
            }
}

Answer 1

您可以修改在gridview列模板中生成的标记。

<asp:TemplateField>
    <ItemTemplate>
       <asp:Literal ID="ltMarkup" runat="server" Text='<%# Eval("DocID") %>'></asp:Literal>
    </ItemTemplate>
 </asp:TemplateField>

然后管理在gridview的rowdatabound事件中生成的链接：

 protected void GridView_RowDataBound(Object sender, GridViewRowEventArgs e)
 {
    if(e.Row.RowType == DataControlRowType.DataRow)
    {
      string[] docs = e.Row.Cells[3].Text.Split(' ');

      var lt = (Literal)e.Row.Cells[3].FindControl("ltMarkup");
      foreach(var d in docs)
          lt.Text +=  String.Format("<a href='{0}'>Link {0}</a><br/>", d);
    }
 }

HTH

gridview合并的行需要来自不同值的单独链接

1 个答案: