REQ:如果多部电话具有相同的最近日期,请以编号最少的电话。我的数据如下。
CustomerID PhoneNumber CreatedDate
1111 1234587 2013-09-10
1111 1243557 2013-09-11
1111 3214562 2009-12-01
2222 7654312 2013-02-05
2222 6544343 2006-07-23
2222 7652135 2006-04-16
2222 5672851 2010-11-16
2222 4726722 1998-06-18
输出如下:
CustomerID PhoneNumber CreatedDate
1111 1234587 2013-09-10
2222 4726722 1998-06-18
答案 0 :(得分:0)
使用两个子查询来确定最大日期和最小电话号码,并将它们与表格本身联系起来
SELECT a.CustomerID, a.PhoneNumber, a.CreatedDate
FROM test a
JOIN (SELECT CustomerID, MAX(CreatedDate) as max_date
FROM test
GROUP BY CustomerID) b ON b.CustomerID = a.CustomerID AND
b.max_date = a.CreatedDate
JOIN (SELECT CustomerID, CreatedDate, MIN(PhoneNumber) min_number
FROM test
GROUP BY CustomerID, CreatedDate) c ON c.CustomerID = a.CustomerID AND
c.min_number = a.PhoneNumber AND
c.CreatedDate = a.CreatedDate
答案 1 :(得分:0)
有帮助吗?
SELECT TOP 1 CreatedDate, MIN(CAST(PhoneNumber AS INT))
FROM [TABLENAME]
GROUP BY CAST(CreatedDate AS DATE)
答案 2 :(得分:0)
另一种选择是在<section class="page-section cta closeBorder">
<div class="container">
<div class="row">
<div class="col-xl-9 mx-auto">
<div class="cta-inner rounded">
<h2 class="section-heading mb-4">
<span class="text-center section-heading-upper">Wordt lid van de nieuwsbrief</span>
<span class="text-center section-heading-lower">Blijf op de hoogte</span>
</h2>
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<b class="pull-left"><em>E-mailadres:</em></b>
<input type="email" class="form-control" name="email">
<input type="submit" class="btn-block subBtn" value="Abonneer!">
</div>
</div>
</div>
</div>
</section>
的音乐会中使用WITH TIES
子句
示例
Row_Number()
返回
Select Top 1 with ties *
From YourTable
Order By Row_Number() over (Partition By CustomerID Order By CreatedDate Desc,PhoneNumber)
答案 3 :(得分:0)
尝试一下:
SELECT
YT.CreatedDate
,MIN(YT.PhoneNumber)
FROM
YourTable YT
GROUP BY
YT.CreatedDate