如何在图像捕获过程中休息?实际上,我需要在图像之间间隔5秒。
此代码每秒可捕获约15-20张图像,但是我需要在图像之间以5秒的间隔拍照
import cv2
import time
import numpy
capture = cv2.VideoCapture(0)
capture.set(3,640)
capture.set(4,480)
img_counter = 0
frame_set = []
start_time = time.time()
while(True):
ret , frame = capture.read()
gray = cv2.cvtColor(frame,cv2.COLOR_BGR2GRAY)
frame_set.append(gray)
cv2.imshow('frame',gray)
if cv2.waitKey(1) & 0xFF == ord('q'):
break
end_time = time.time()
elapsed = end_time - start_time
img_name = "opencv_frame_{}.png".format(img_counter)
cv2.imwrite(img_name,frame)
print("{} written!".format(img_counter))
img_counter +=1
if elapsed > 1:
capture.release()
cv2.destroyAllWindows()
time.sleep(3)
答案 0 :(得分:0)
您需要一个if语句来检查所需时间是否已过去。使用已经导入的时间包,您可以执行以下操作:
import cv2
import time
capture = cv2.VideoCapture(0)
capture.set(3, 640)
capture.set(4, 480)
img_counter = 0
frame_set = []
start_time = time.time()
while True:
ret, frame = capture.read()
gray = cv2.cvtColor(frame, cv2.COLOR_BGR2GRAY)
cv2.imshow('frame', gray)
if cv2.waitKey(1) & 0xFF == ord('q'):
break
if time.time() - start_time >= 5: #<---- Check if 5 sec passed
img_name = "opencv_frame_{}.png".format(img_counter)
cv2.imwrite(img_name, frame)
print("{} written!".format(img_counter))
start_time = time.time()
img_counter += 1
以上脚本将每5秒将RGB帧保存到工作目录中。