mysqldb.js
const mysqlDatabasePool = mysql.createPool({
connectionLimit: 50,
host: process.env.MYSQL_HOST,
user: process.env.MYSQL_USERNAME,
password: process.env.MYSQL_PASSWORD,
port: process.env.MYSQL_PORT,
database: process.env.MYSQL_DATABASE
});
mysqlDatabasePool.getConnection({
//Basic sanity checking code here
});
mysqlDatabasePool.query = util.promisify(mysqlDatabasePool.query);
module.exports = mysqlDatabasePool;
employeeController.js
var pool = require("mysqldb");
pool.query("SELECT CategoryID, CategoryIcon FROM Categories WHERE CategoryName = ?", [categoryName], function(error, results, fields) {
if(results !== null && results.length > 0) {
for(var i = 0; i < results.length; i++) {
outputData[i] = results[i];
var subCategories = pool.query("SELECT SubcategoryID FROM Subcategories WHERE CategoryID = ?", [results[i].CategoryID], function(error, results, fields) {
return results;
});
if(subCategories.length > 0)
outputData[i]["Subcategories"] = subCategories;
else
outputData[i]["Subcategories"] = null;
}
}
});
outputData[i]["Subcategories"]
的内容始终为null
,因为它始终可用,因此应该具有子类别的集合。我尝试通过在第二个await/async
之前放置await并使第一个pool.query
关闭函数异步来实现pool.query
。
应如何处理?
答案 0 :(得分:0)
作为参数传递给pool.query
的函数是一个回调。这意味着您不知道何时执行。
您可以使用async / await阻止呼叫,直到pool.query给您结果为止。
您可能需要在util.promisify
上使用pool.query
才能返回Promise。
try {
const results = await pool.query("SELECT CategoryID, CategoryIcon FROM Categories WHERE CategoryName = ?", [categoryName]);
if(results !== null && results.length > 0) {
for(var i = 0; i < results.length; i++) {
outputData[i] = results[i];
const subCategories = await pool.query("SELECT SubcategoryID FROM Subcategories WHERE CategoryID = ?", [results[i].CategoryID]);
if(subCategories.length > 0)
outputData[i]["Subcategories"] = subCategories;
else
outputData[i]["Subcategories"] = null;
}
}
} catch(error) {
console.log(error)
// Deal with the error
}
上面是如何使用async/await
语法的示例。记住要使用关键字await
,周围的功能必须标记为async
。