Question

简单地。如果我想将产品添加到购物车php中工作，但是如果我尝试将产品添加到特定表中则无法工作。我试图设置if（！con）{echo“ test”;}或类似的地方我可以找出问题所在，但是php不会显示任何错误。所有会话均正常工作，数据库已连接。有任何建议吗？问题可能在mysql表中，但不会显示任何内容。上次我在varchar中出错时，sql显示了一些东西但这一次...什么都没有！对不起我的英语差错xD！

Function.php

function favor(){
    if(isset($_GET['add_favor'])){

        global $con;
        $ip = getIp();
        $pro_id = $_GET['add_favor'];
        $user = $_SESSION['customer_username'];
        $check_favor = "SELECT * FROM favorite WHERE username='$user' AND pro_id='$pro_id'";
        $run_fcheck = mysqli_query($con, $check_favor);

        if(mysqli_num_rows($run_fcheck) == 0){

            $insert_favor = "INSERT INTO favorite (pro_id,username) VALUES ('$pro_id','$user')";
            $run_favor = mysqli_query($con, $insert_favor);

            echo "<script>window.open('index.php','_self')</script>";
        }
    }
}

index.php

   <?php include 'header.php'; ?>
    <?php cart(); ?>
    <?php favor(); ?>
    <div class="sidebar">
    <div class="spacer2"></div>
        <?php getCats(); ?>
    </div>
    <div class="content">
    <li style="margin-top:10px;" class="search42">
        <form method="get" action="results.php" enctype="multipart/form-data">
            <input class="afsc2g" type="text" name="user_query" placeholder="Search.." name="search">
            <button type="submit" name="search"><i class="fa fa-search"></i></button>
        </form></li>
        <div class="content-nav">
            <a href="shopping_cart.php"><i class="fas fa-shopping-cart"></i><span> (<?php total_price(); ?> din.)</span></a>
        </div>
    <div class="products" style="height:200px;">
<?php
        if(isset($_GET['pro_id'])){

            $user = $_SESSION['customer_username'];
            $product_id = $_GET['pro_id'];
            $get_pro = "SELECT * FROM products WHERE product_id='$product_id'";
            $run_pro = mysqli_query($con, $get_pro); 

            while($row_pro=mysqli_fetch_array($run_pro)){

                $pro_id = $row_pro['product_id'];
                $pro_title = $row_pro['product_title'];
                $pro_price = $row_pro['product_price'];
                $pro_desc = $row_pro['product_desc'];
                $pro_image = $row_pro['product_image'];

                echo "<div class='divbox'>
                <div style='float:left'>
                <h2 style='font-size:27px'>$pro_title</h2>
                <img style='border-top:3px solid #1585bd;' width='450px' height='450px' src='../assests/pictures/products/$pro_image'/>
                </div>
                <div class='ukorpu'>
                <a class='add_favor'><a class='button' href='index.php?add_favor=$pro_id'><i class='fas fa-star'></i></a>
                <a class='cena' style='font-size:23px;'>$pro_price  din.</a> 
                <a style='position:absolute;left:72px;top:50px;font-size:14px;'>sa PDV-om</a>
                <a class='bnau2' style='font-weight:bold;' href='index.php?add_cart=$pro_id'><i class='fas fa-shopping-cart'></i> Dodaj u korpu</a></p>
                </div></div>
                <div class='desc'>
                <div class='desc-desc'>
                $pro_desc
                </div>
                </div>";

            }
    }
?>

MySQL表：

PHP不会将数据插入表中

0 个答案: