Question

我想出了以下方法来创建此WinForms控件：

using System;
using System.IO;
using System.Runtime.InteropServices;
using System.Windows.Forms;

public class ConsoleWindow : Control
{
    [DllImport("kernel32.dll", CharSet = CharSet.Unicode, CallingConvention = CallingConvention.StdCall, SetLastError = true)]
    [return: MarshalAs(UnmanagedType.Bool)]
    private static extern bool AllocConsole();

    [DllImport("kernel32.dll", CharSet = CharSet.Unicode, CallingConvention = CallingConvention.StdCall, SetLastError = true)]
    [return: MarshalAs(UnmanagedType.Bool)]
    private static extern bool FreeConsole();

    [DllImport("kernel32.dll")]
    static extern IntPtr GetConsoleWindow();

    [DllImport("user32.dll", SetLastError = true)]
    static extern IntPtr SetParent(IntPtr hWndChild, IntPtr hWndNewParent);

    [DllImport("user32.dll", SetLastError = true)]
    static extern bool SetWindowPos(IntPtr hWnd, IntPtr hWndInsertAfter, int X, int Y, int cx, int cy, uint uFlags);

    [DllImport("user32.dll")]
    public static extern int SetWindowLong(IntPtr hWnd, int nIndex, int dwNewLong);

    private static ConsoleWindow _theWindow;

    public ConsoleWindow()
    {
        if (!DesignMode)
        {
            if (_theWindow != null)
            {
                throw new Exception("An application can have only one ConsoleWindow");
            }
            _theWindow = this;
            AllocConsole();
            var newOut = new StreamWriter(Console.OpenStandardOutput()) { AutoFlush = true };
            Console.SetOut(newOut);
            Console.SetError(newOut);

            var consoleHwnd = GetConsoleWindow();

            SizeChanged += (sender, args) =>
            {
                SetWindowPos(consoleHwnd, IntPtr.Zero, 0, 0, Width, Height, 0);
            };

            SetWindowLong(consoleHwnd, -16 /*GWL_STYLE*/, 0x50000000 /* WS_CHILD|WS_VISIBLE*/);
            SetParent(consoleHwnd, Handle);
            SetWindowPos(consoleHwnd, IntPtr.Zero, 0, 0, 0, 0, 0);
        }
    }

    protected override void Dispose(bool disposing)
    {
        if (disposing && _theWindow != null)
        {
            FreeConsole();
            _theWindow = null;
        }

        base.Dispose(disposing);
    }
}

...然后可以通过XAML在WPF应用程序中使用它，例如：

    <WindowsFormsHost>
        <WindowsFormsHost.Child>
            <controls:ConsoleWindow></controls:ConsoleWindow>
        </WindowsFormsHost.Child>
    </WindowsFormsHost>

主要有效，但鼠标交互似乎受到了损害。当您创建一个控制台窗口（通常作为顶级窗口运行）时，您可以使用鼠标单击/拖动任意选择，但是像我一样将其作为子控件作为父控件后，该选项将不再起作用。我可以右键单击以调用控制台窗口的上下文菜单来选择/复制所有文本，但是我无法进行单击/拖动选择。

是否可以解决此问题（可能是样式丢失/样式错误或消息路由？），以便我可以按预期方式与控制台窗口进行交互，或者以这种方式为控制台窗口做父母有根本性的问题吗？ >

Answer 1

Dave Kerr编写了一个控件，可以解决您的问题。

使用此链接：https://www.codeproject.com/articles/335909/embedding-a-console-in-a-c-application

应该添加此内容，因为它使用了包含在链接中的名为ProcessInterface的类。

最后，这部分代码就是解决方案：

/// <summary>
        /// Handles the KeyDown event of the richTextBoxConsole control.
        /// </summary>
        /// <param name="sender">The source of the event.</param>
        /// <param name="e">The <see cref="System.Windows.Forms.KeyEventArgs"/> instance containing the event data.</param>
        void richTextBoxConsole_KeyDown(object sender, KeyEventArgs e)
        {
            bool inReadOnlyZone = richTextBoxConsole.Selection.Start.CompareTo(inputStart) < 0;

            //  If we're at the input point and it's backspace, bail.
            if (inReadOnlyZone && e.Key == Key.Back)
                e.Handled = true;;

            //  Are we in the read-only zone?
            if (inReadOnlyZone)
            {
                //  Allow arrows and Ctrl-C.
                if (!(e.Key == Key.Left ||
                    e.Key == Key.Right ||
                    e.Key == Key.Up ||
                    e.Key == Key.Down ||
                    (e.Key == Key.C && Keyboard.Modifiers.HasFlag(ModifierKeys.Control))))
                {
                    e.Handled = true;
                }
            }

            //  Is it the return key?
            if (e.Key == Key.Return)
            {
                //  Get the input.
                //todostring input = richTextBoxConsole.Text.Substring(inputStart, (richTextBoxConsole.SelectionStart) - inputStart);

                //  Write the input (without echoing).
                //todoWriteInput(input, Colors.White, false);
            }
        }

将其作为WPF应用程序的父项后，为什么不能与控制台窗口进行交互？

1 个答案: