Question

以下是我根据此处给出的示例编写的代码Google Map V3 Demo

我的问题是点击任何打开信息窗口的标记总是在一个固定点我的意思是如果我有4个标记marker1，marker2，marker3，marker4 ..如果我点击mark1或mark2或mark3或mark4信息窗口是始终在marker4处打开，也是marker4的信息

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>jQuery + Google Maps API v3 Demo</title>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
<script type="text/javascript" src="http://maps.google.com/maps/api/js?sensor=true"></script>
<script type="text/javascript">
    var map;
    var arrMarkers = [];
    var arrInfoWindows = [];

    function mapInit(){
        var centerCoord = new google.maps.LatLng(17.22, 78.29);
        var mapOptions = {
            zoom: 6,
            center: centerCoord,
            mapTypeId: google.maps.MapTypeId.TERRAIN
        };
        map = new google.maps.Map(document.getElementById("map"), mapOptions);

        $.getJSON("mapDB.php", function(mapPoints){
                        for (var i = 0; i < mapPoints.length; i++) {
                            var marker = new google.maps.Marker({
                                                position: new google.maps.LatLng(mapPoints[i].latitude,mapPoints[i].longitude),
                                                map: map,
                                                title: "test"+i
                            });
                            arrMarkers[i] = marker;
                            var infowindow = new google.maps.InfoWindow({
                                                content: "<h3>Test this</h3>"+i
                            });
                            arrInfoWindows[i] = infowindow;
                            google.maps.event.addListener(marker, 'click', function() {
                                                infowindow.open(map, marker);
                            });


                    }

                });
    }
    $(function(){
        mapInit();

    });
</script>
<style type="text/css" media="screen">
    img { border: 0; }
    #map{
        width: 500px;
        height: 600px;;


    }
    #content {
        position: fixed;
        top: 10px;
        left: 800px;
        margin: 30px;
    }
</style>
</head>

<body>
    <div id="container">
        <div id="map"></div>
    </div>

</body>
</html>

感谢您的帮助问候基兰

Answer 1

我认为你对变量有一些范围问题。没有太多时间深入挖掘。我把这个jsFiddle放在一起：http://jsfiddle.net/rcravens/T7HwX/2/

以下是我更新后的代码：

    var count = mapPoints.length;
    for (var i = 0; i < count; i++) {
        var latlng = new google.maps.LatLng(mapPoints[i].latitude,mapPoints[i].longitude);
        var title = "test" + i;
        var marker = new google.maps.Marker({
            position: latlng,
            map: map,
            title: title
        });
        arrMarkers[i] = marker;
        var infowindow = new google.maps.InfoWindow();
        arrInfoWindows[i] = infowindow;
        marker.myHtml = "<h3>Test this " + i + "</h3>";
        google.maps.event.addListener(marker, 'click', function () {
                infowindow.setContent(this.myHtml);
                infowindow.open(map, this);
            });

    }

主要是创建'addListener'。

希望这有帮助。

鲍勃

Jquery Google Maps V3 - 信息窗口始终固定为一个标记

1 个答案: