使用google api,我必须设置本质上相同但产生不同结果的代码集。
两者都只需输入一个fileId和两个parentId,一个就可以删除,一个要与Google api一起添加。本质上,这是Google驱动器中文件的移动操作。可以正常工作的代码仅需要(from, to, file) => {}
的签名,而没有传递给Google Picker Call回调中的字段的签名。 (Link to Picker API Docs)
第一个返回成功,第二个得到来自api的响应,指出存在解析错误,关于导致解析错误的原因很少。
moveFile = (from, to, file) => {
return gapi.client.drive.files
.update({
addParents: to,
removeParents: from,
fileId: file,
})
.then((res) => {
logger.log(funcname, `Moved File: ${file} from ${from} to ${to}.`);
return res.result;
});
};
function folderSelectedCallback(folderData, fileData) {
//folderData and fileData both have the same structure
//{action: 'type of action',
//docs: [{Array Of Document Objects}],
//viewToken: [Array of unused data]}
//Docs Array Objects Structure (only used properties listed.)
//{ id: 'string ID of the File',
//parentId: 'string ID of the parent folder'}
if (folderData.action === 'picked') {
console.log('folderSelectedCallback(): called.');
console.log('File Data: ', fileData);
console.log('Folder Data: ', folderData);
const files = fileData.docs;
const folder = folderData.docs[0];
console.log(files);
console.log(folder);
files.forEach((f) => {
gapi.client.drive.files
.update({
addParents: to,
removeParents: from,
fileId: file,
})
.then((res) => {
console.log(funcname, `Moved File: ${file} from ${from} to ${to}.`);
return res.result;
}).catch(err => console.error(err));
});
}
}
我需要解决更多信息吗?
答案 0 :(得分:0)
function folderSelectedCallback(folderData, fileData) {
if (folderData.action === 'picked') {
console.log('folderSelectedCallback(): called.');
console.log('File Data: ', fileData);
console.log('Folder Data: ', folderData);
const files = fileData.docs;
const folder = folderData.docs[0];
console.log(files);
console.log(folder);
files.forEach((f) => {
const options = {
addParents: folder.id,
removeParents: (typeof f.parentId !== 'undefined') ? f.parentId : '',
fileId: f.id
};
gapi.client
.request({
path: `drive/v3/files/${options.fileId}`,
method: 'PATCH',
params: options,
body: options
})
.then((response) => console.log(response))
.catch((err) => console.error(err));
});
}
}
出于某种原因,以这种方式使用gapi.client.request
可以正常工作。