Question

由于{％for％}循环，重复了我在HTML中的文本。我已经尝试将{％if％}移出{％for％}。然后我消失了。

这是我的html模板

{% for city in cities %}
  {% if city.author.access_challenge %}
    <p class="small text-center"> In order to get information about this  contact us through almaz@protonmail.com </p>
  {% else %}
    <table class="table table-hover text-left col-sm-12" style="table-layout: fixed; word-wrap: break-word;">
     <tbody>
      <tr>
       <td><a class="text-uppercase" href="{% url 'users:address' city.pk %}">{{ city.city }}</a></td>
      </tr>
     </tbody>
    </table>
{% endif %}
{% endfor %}

这是我的views.py

def cities(request, pk):

    country = Post.objects.get(id=pk).country
    cities = Post.objects.filter(country=country).distinct('city')

    context = {
        'cities':cities,
        'country':country
    }

    return render(request, 'users/cities.html', context)

我也试图这样更改views.py：

def cities(request, pk):

    country = Post.objects.get(id=pk).country
    ci = Post.objects.filter(country=country).distinct('city')
    cit = list(ci)
    for city in cit:
        for cities in cit:
            context = {
                'cities':cities,
                'country':country
            }

    return render(request, 'users/cities.html', context)

但是当我使用for循环时，我收到一个错误，指出Post是不可迭代的。

Answer 1

在您的代码中尝试forloop.first。例如：

输入：

{% for product in products %}
    {% if forloop.first == True %}
        First time through!
    {% else %}
        Not the first time.
    {% endif %}
{% endfor %}

输出：

First time through!
Not the first time.
Not the first time.

针对您的情况：

{% for city in cities %}
    {% if city.author.access_challenge and forloop.first == True %}  
        <p class="small text-center"> In order to get information about this  contact us through almaz@protonmail.com </p>
    {% else %}
        <table class="table table-hover text-left col-sm-12" style="table-layout: fixed; word-wrap: break-word;">
         <tbody>
          <tr>
           <td><a class="text-uppercase" href="{% url 'users:address' city.pk %}">{{ city.city }}</a></td>
          </tr>
         </tbody>
        </table>
    {% endif %}
{% endfor %}

Answer 2

完成时

cities = Post.objects.filter(country=country).distinct('city')

您尝试获取的是所有不同城市的列表，但是您获取的是Post对象的查询集。

要获取发布模型中所有不同城市的列表，请执行以下操作：

Post.objects.all().values_list('city').distinct()

Answer 3

我这样解决了：

我的views.py现在：

def cities(request, pk):

    country = Post.objects.get(id=pk).country
    cities = Post.objects.filter(country=country).distinct('city')
    author = Post.objects.get(id=pk).author

    context = {
        'cities':cities,
        'country':country,
        'author':author,

    }

    return render(request, 'users/cities.html', context)

我的views.py曾经是：

def cities(request, pk):

    country = Post.objects.get(id=pk).country
    cities = Post.objects.filter(country=country).distinct('city')

    context = {
        'cities':cities,
        'country':country
    }

    return render(request, 'users/cities.html', context)

在使用相同代码之前，我的HTML有错误。但是现在它可以正常工作了：

  {% if author.access_challenge %}

    <p class="text-center col-sm-12"> In order to get info about this country contact <strong>emeupci@protonmail.com</strong></p>

    {% else %}

    {% for city in cities %}
    <table class="table table-hover text-left col-sm-12" style="table-layout: fixed; word-wrap: break-word;">
       <tbody>
        <tr>
         <td><a class="text-uppercase" href="{% url 'users:address' city.pk %}">{{ city.city }}</a></td>
        </tr>
       </tbody>
      </table>
    {% endfor %}

    {% endif %}

在我的django HTML模板中，由于{％for city in city％}循环而重复了我的文本

3 个答案: