Question

我在另一个视图中有一个名为UIPopoverController的{{1}}。我想知道的是，如果在当前的弹出视图中按下popover，我如何解除弹出窗口？提前谢谢。

Answer 1

我总是觉得奇怪的是，UIViewController通过它的“contentSizeForViewInPopover”属性知道弹出窗口应该有多大，但是没有保留指向UIPopoverController本身的指针。我总是最后添加：

@property (nonatomic,assign) UIPopoverController* popover;

到我的UIViewController类，并在创建弹出窗口时设置它。然后从UIViewController中的任何东西，我可以这样做来解除popover：

[popover dismissPopoverAnimated:YES];

Answer 2

您可以使用NSNotification告诉其他视图忽略它的弹出视图。

使用示例：

// Add an observer that will respond to our notification.
[[NSNotificationCenter defaultCenter] addObserver:self // <- This is the object that will has the selector that we want to run (the same one we use in the next line).
                                         selector:@selector(doSomething:) // <- This is the selector we want to run.
                                             name:@"doSomethingNow" // <- This is notification name we will send to activate our observer's selector.
                                           object:nil]; // Don't worry about this for now.


// Post the notification. This has the same name as our observer above, so our 'doSomething' selector should be run.
[[NSNotificationCenter defaultCenter] postNotificationName:@"doSomethingNow" object:nil];


// the function specified in the same class where we defined the addObserver
- (void)doSomething:(NSNotification *)pNotification {
    NSLog(@"Received Notification..."); 
}

从另一个视图中关闭UIPopoverController

2 个答案: