我试图用日期填充gridview。
例如今天是2/18/2019,下一个日期在30天内是3/20/2019。所以所需的输出应该像这样
No. Date
1 3/20/2019
2 4/19/2019
3 5/19/2019
等
但结果是
No. Date
1 3/20/2019
2 3/20/2019
3 3/20/2019
等
到目前为止,这是我的代码。
Dim termCounter As Integer = 36
Dim today As DateTime = DateTime.Today
Dim dueDate As DateTime = today.AddDays(30)
Dim dtable As DataTable = New DataTable()
dtable.Columns.Add("No.")
dtable.Columns.Add("Payment Date")
Dim RowValues As Object() = {"", ""}
Dim dRow As DataRow
Dim tmpDate As Date
For i As Integer = 1 To termCounter
If GridAmortSched.RowCount <= 0 Then
RowValues(0) = i
RowValues(1) = dueDate.ToShortDateString
dRow = dtable.Rows.Add(RowValues)
Else
tmpDate = GridAmortSched.Rows(GridAmortSched.RowCount - 1).Cells(1).Value.ToString()
RowValues(0) = i
RowValues(1) = tmpDate.AddDays(30).ToShortDateString
dRow = dtable.Rows.Add(RowValues)
End If
Next
dtable.AcceptChanges()
GridAmortSched.DataSource = dtable
答案 0 :(得分:0)
在通常情况下,代码的行为与您要求的一样,而不是您想要的:-)。
每次循环时,都从同一源设置tmpDate
,然后在两行之后,将值放入RowValues
中。 :
tmpDate = GridAmortSched.Rows(GridAmortSched.RowCount - 1).Cells(1).Value.ToString()
您不会通过i
来调整信号源,也不会增加它。 AddDays
时,您也不会调整原始值(由于分配方式和时间的原因,该值将无效)。
一个。第一个是根据循环值对要添加的天数编制索引-对以下代码进行简单修改即可实现这一点。这是一个快速修复,将来可能很难维护-更重要的是,如果您更改诸如循环起始点之类的内容,则更难发现。
RowValues(1) = tmpDate.AddDays(30*i).ToShortDateString
两个。另一个选项是解决代码逻辑。设置基线值,然后在循环中递增它。
Dim tmpDate As Date
tmpDate = GridAmortSched.Rows(GridAmortSched.RowCount - 1).Cells(1).Value.ToString() '*** Moved outside of loop
For i As Integer = 1 To termCounter
If GridAmortSched.RowCount <= 0 Then
RowValues(0) = i
RowValues(1) = dueDate.ToShortDateString
dRow = dtable.Rows.Add(RowValues)
Else
RowValues(0) = i
tmpDate = tmpDate.AddDays(30) '*** Increment date every time it passes here
RowValues(1) = tmpDate.ToShortDateString '*** Assign the new value
dRow = dtable.Rows.Add(RowValues)
End If
Next
dtable.AcceptChanges()
GridAmortSched.DataSource = dtable