Question

我已将数据整理到列表结构中……

[['keychain: "keychainname.keychain-db"', 
'version: 512', 
'class: 0x0000000F ', 
'attributes:\n   long string containing : and \n that needs to be split up into a list (by newline) of dictionaries (by regex and/or split() function) '], 
['keychain: "keychainname.keychain-db"', 
'version: 512', 
'class: 0x0000000F ', 
'attributes:\n   long string that needs to be split up '], 
['keychain: "keychainname.keychain-db"', 
'version: 512', 
'class: 0x0000000F ', 
'attributes:\n    long string that needs to be split up']]

我正在尝试使用一种理解方法来获取列表中的每个项目，并将其拆分为以下格式的字典：

['{'keychain': 'keychainname.db', 
'version': '512', 
'class': '0x0000000F', 
'attribute':\n   long string containing : and \n that needs to be split up into a dictionary (by newline) of dictionaries (by regex and/or split() function) '}']

以下for循环似乎有效……

newdata = []
for item in data:
    eachdict = {}
    for each in item:
        new = each.split(':', 1)
        eachdict[new[0]] = new[1]
        newdata.append(eachdict)

但是我的理解力却没有……

newdata = [[{key:value for item in data} for line in item] for key, value in (line.split(':', 1))]

此理解已运行，但嵌套未正确完成...

newdata = [{key:value for item in data} for key, value in (item.split(':', 1),)]

我刚刚开始学习理解，并且已经能够成功地使用它们将数据转换为嵌套列表的上述格式，但是当我进入三个层次时，我一直在努力理解嵌套然后从列表切换到字典。

我希望对如何解决该问题提出一些建议。

要获得加分，我还需要将attribute键中的长字符串也拆分成字典字典。我希望能够引用“ Alis”键，“ labl”键等。如果我首先在上面的示例中学习如何使用嵌套的理解，我可能可以自己弄清楚。

attributes:\n
    "alis"<blob>="com.company.companyvpn.production.vpn.5D5AF9C525C25350E9CD5CEBED824BFD60E42110"\n
    "cenc"<uint32>=0x00000003 \n
    "ctyp"<uint32>=0x00000001 \n
    "hpky"<blob>=0xB7262C7D5BCC976744F8CA6DE5A80B755622D434  "\\267&,}[\\314\\227gD\\370\\312m\\345\\250\\013uV"\\3244"\n
    "issu"<blob>=0x306E3128302606035504030C1F4170706C6520436F72706F726174652056504E20436C69656E7420434120313120301E060355040B0C1743657274696669636174696F6E20417574686F7269747931133011060355040A0C0A4170706C6520496E632E310B3009060355040613025553  "0n1(0&\\006\\003U\\004\\003\\014\\037Company Corporate VPN Client CA 11 0\\036\\006\\003U\\004\\013\\014\\027Certification Authority1\\0230\\021\\006\\003U\\004\\012\\014\\012Company Inc.1\\0130\\011\\006\\003U\\004\\006\\023\\002US"\n
    "labl"<blob>="com.company.companyvpn.production.vpn.5D5AF9C525C25350E9CD5CEBED824BFD60E42110"\n
    "skid"<blob>=0xB7262C7D5BCC976744F8CA6DE5A80B755622D434  "\\267&,}[\\314\\227gD\\370\\312m\\345\\250\\013uV"\\3244"\n    "snbr"<blob>=0x060A02F6F9880D69  "\\006\\012\\002\\366\\371\\210\\015i"\n
    "subj"<blob>=0x3061315F305D06035504030C56636F6D2E6170706C652E6973742E64732E6170706C65636F6E6E656374322E70726F64756374696F6E2E76706E2E35443541463943353235433235333530453943443543454245443832344246443630453432313130  "0a1_0]\\006\\003U\\004\\003\\014Vcom.company.companyvpn.production.vpn.5D5AF9C525C25350E9CD5CEBED824BFD60E42110"'

对于上下文...

我正在Mac上使用“ security dump-keychain”的输出来制作一个不错的Python数据结构来查找密钥。该命令的check_output是一个长字符串，带有一些不一致的格式和嵌入的换行符，我需要清理掉换行符才能将数据放入字典的字典列表中。

对于那些对Mac管理员主题感兴趣的人，这是我们可以删除重置AD密码时保存Active Directory密码的项目，这样该帐户就不会被锁定，例如，Outlook向Exchange展示旧密码一遍又一遍。

Answer 1

这可能是一种方法：

data = [['keychain: "keychainname.keychain-db"',  'version: 512',  'class: 0x0000000F ',  'attributes:\n   long string containing : and \n that needs to be split up into a list (by newline) of dictionaries (by regex and/or split() function) '],  ['keychain: "keychainname.keychain-db"',  'version: 512',  'class: 0x0000000F ',  'attributes:\n   long string that needs to be split up '],  ['keychain: "keychainname.keychain-db"',  'version: 512',  'class: 0x0000000F ',  'attributes:\n    long string that needs to be split up']]

result = [dict([item.split(':', 1) for item in items]) for items in data]

>>> [{'keychain': ' "keychainname.keychain-db"', 'version': ' 512', 'class': ' 0x0000000F ', 'attributes': '\n   long string containing : and \n that needs to be split up into a list (by newline) of dictionaries (by regex and/or split() function) '}, {'keychain': ' "keychainname.keychain-db"', 'version': ' 512', 'class': ' 0x0000000F ', 'attributes': '\n   long string that needs to be split up '}, {'keychain': ' "keychainname.keychain-db"', 'version': ' 512', 'class': ' 0x0000000F ', 'attributes': '\n    long string that needs to be split up'}]

split将每个字符串分成一个键，值对。内部列表理解在单个项目中的每个键，值对之间循环。外部列表理解遍历主列表中的每个项目。

将嵌套列表更改为字典列表的理解

1 个答案: