React Native返回Promise而不是值Firestore

时间:2019-02-12 18:21:07

标签: javascript firebase react-native google-cloud-firestore

因此,我试图从保存在我的用户集合中的ID数组(已填充)上从Firestore basen获取多个文档。我首先获取ID,然后有一个map函数,该函数从食谱集合中查找每个文档并将其分配给变量数据。问题在于,我不仅获得每个ID的结果,还获得每个ID的承诺。我该如何解决这个问题以便仅获取数据?

export const yummedRecipesFetch = () => {
    const { currentUser } = firebase.auth();
    return (dispatch) => {
        firebase.firestore().collection(`users`).doc(currentUser.uid)
            .onSnapshot(function(doc) {
                var data = doc.data().yummed.map(function (recipeId) {
                    return firebase.firestore().collection(`recipes`).doc(recipeId).get().then(function(doc) {
                        return { id: doc.id, ...doc.data()};
                    })                    
                })
                console.log(data)
                dispatch({ type: YUMMED_RECIPES_FETCH_SUCCESS, payload: data })
            });
    };
};

1 个答案:

答案 0 :(得分:1)

使用Promise.all上方的建议

export const yummedRecipesFetch = () => {
    const { currentUser } = firebase.auth();
    return (dispatch) => {
        firebase.firestore().collection(`users`).doc(currentUser.uid)
            .onSnapshot(function(doc) {
                var data = doc.data().yummed.map(function (recipeId) {
                    return firebase.firestore().collection(`recipes`).doc(recipeId).get().then(function(doc) {
                        return { id: doc.id, ...doc.data()};
                    })                    
                })
                Promise.all( data).then(function(values) {
                    dispatch({ type: YUMMED_RECIPES_FETCH_SUCCESS, payload: values })
                })
            });
    };
};