我该如何遍历json并从以下json字符串中提取每个任务的值(即“ AMS Upgrade”和“ BMS works”是任务),我尝试使用下面的代码,但未成功。
请注意,AMS升级和BMS的工作原理是变量 ,因此代码不应引用它们
在每个循环中,我希望能够控制台以下日志
第一个循环
任务说明:AMS升级
总计:30667.303111791967
完成百分比:1.0
索赔值:25799.788761888347
第二个循环
任务说明:BMS有效
总计:35722.8761704046
%完成至结束:0.1
索赔值:3572.2876170404597
var data = `{"line_items": {"AMS Upgrade": [{"Total": 30667.303111791967}, {"% Complete to end": 1.0}, {"value claimed": 25799.788761888347}], "BMS works": [{"Total": 35722.8761704046}, {"% Complete to end": 0.1}, {"value claimed": 3572.2876170404597}]}}`
var obj = JSON.parse(data);
console.log("processing data...");
console.log(obj);
console.log(obj.line_items[1].Total);
答案 0 :(得分:2)
const obj = {
"line_items": {
"AMS Upgrade": [{
"Total": 30667.303111791967
}, {
"% Complete to end": 1.0
}, {
"value claimed": 25799.788761888347
}],
"BMS works": [{
"Total": 35722.8761704046
}, {
"% Complete to end": 0.1
}, {
"value claimed": 3572.2876170404597
}]
}
};
const totals = Object.keys(obj.line_items).map(valInner => obj.line_items[valInner][0].Total);
console.log(totals);
/* Updated code for inner values */
Object.keys(obj.line_items).forEach(valInner => {
obj.line_items[valInner].forEach((val) => {
for (const i in val) {
console.log(`${i} = ${val[i]}`);
}
});
});
答案 1 :(得分:2)
这是使用for..in
的方式。
const data = {"line_items":
{"AMS Upgrade": [
{"Total": 30667.303111791967},
{"%Complete to end": 1.0},
{"value claimed": 25799.788761888347}],
"BMSworks": [
{"Total": 35722.8761704046},
{"%Complete to end": 0.1},
{"value claimed": 3572.2876170404597}]
}
}
let totals = [];
for(let key in data.line_items){
totals.push(data.line_items[key][0].Total);
}
console.log(totals)
//Combining all other like Total
for(let key in data.line_items){
console.log("Task Description:" + key);
data.line_items[key].forEach(value => {
let k = console.log(`${Object.keys(value)}:${Object.values(value)[0]}`)
})
}
答案 2 :(得分:1)
您可以获取值并从值中获取总计。由于在您的结构中总数仅位于第0个索引,因此如果顺序不固定(可以使用find),则可以直接访问第0个索引。
let obj = {"line_items": {"AMS Upgrade": [{"Total": 30667.303111791967}, {"% Complete to end": 1.0}, {"value claimed": 25799.788761888347}], "BMS works": [{"Total": 35722.8761704046}, {"% Complete to end": 0.1}, {"value claimed": 3572.2876170404597}]}}
let Total = Object.values(obj.line_items).map(e=>e[0].Total)
console.log(Total)
我如何遍历json并在每次运行时获取所有这些值 名称,总数,%_ complete_to_end:和value_claimed一起
let obj = {"line_items": {"AMS Upgrade": [{"Total": 30667.303111791967}, {"% Complete to end": 1.0}, {"value claimed": 25799.788761888347}], "BMS works": [{"Total": 35722.8761704046}, {"% Complete to end": 0.1}, {"value claimed": 3572.2876170404597}]}}
let Total = Object.values(obj.line_items).map(e=> e.map(el=> Object.values(el)))
console.log(Total)
答案 3 :(得分:1)
因为您希望这些项目为变量。寻找theKeyWeWantToget
变量。
var data = `{"line_items": {"AMS Upgrade": [{"Total": 30667.303111791967}, {"% Complete to end": 1.0}, {"value claimed": 25799.788761888347}], "BMS works": [{"Total": 35722.8761704046}, {"% Complete to end": 0.1}, {"value claimed": 3572.2876170404597}]}}`
var obj = JSON.parse(data);
console.log("processing data...");
console.log(obj);
var theKeyWeWantToget = "AMS Upgrade";
console.log(obj.line_items[theKeyWeWantToget][0].Total);
theKeyWeWantToget = "BMS works";
console.log(obj.line_items[theKeyWeWantToget][0].Total);
答案 4 :(得分:0)
这是您的JSON字符串/对象
{
"line_items": {
"AMS Upgrade": [{
"Total": 30667.303111791967
}, {
"% Complete to end": 1.0
}, {
"value claimed": 25799.788761888347
}],
"BMS works": [{
"Total": 35722.8761704046
}, {
"% Complete to end": 0.1
}, {
"value claimed": 3572.2876170404597
}]
}
}
访问总数应为
var totals=[]; //array to store totals.
for(var key in obj.line_items)
{
totals.push(obj.line_items[key][0].Total);
}
答案 5 :(得分:0)
像这样尝试
var obj = JSON.parse(data);
console.log("processing data...");
console.log(obj);
console.log(obj.line_items["AMS Upgrade"][0]);
line_itmes提交了“ AMS升级”,然后“ AMS升级”了数组。因此,您必须通过数组进行访问。
答案 6 :(得分:0)
ES6变体:无论您的总指数处于什么水平,都可以使用。
// ES6 variant.
const test = {
"line_items": {
"AMS Upgrade": [{
"Total": 30667.303111791967
}, {
"% Complete to end": 1.0
}, {
"value claimed": 25799.788761888347
}],
"BMS works": [{
"Total": 35722.8761704046
}, {
"% Complete to end": 0.1
}, {
"value claimed": 3572.2876170404597
}]
}
};
console.log(test["line_items"]["AMS Upgrade"].map(key => key['Total']).filter(val => !!val)[0]);
console.log(test["line_items"]["BMS works"].map(key => key['Total']).filter(val => !!val)[0]);
答案 7 :(得分:0)
使用您的原始结构,以下方法将起作用:
Object.keys(obj.line_items).forEach(key => console.log(obj.line_items[key][0].Total))
您可以改进JSON的结构,使其使用起来更容易。如果您对源数据有控制权,我将建议采取以下措施:
const data = { line_items: [
{
name: "AMS Upgrade"
total: 30667.303111791967,
%_complete_to_end: 1.0,
value_claimed: 25799.788761888347
},
{
name: "BMSworks",
total: 35722.8761704046,
%_complete_to_end: 0.1,
value_claimed: 3572.2876170404597
}
]}
答案 8 :(得分:0)
在第一部分中,我只是解析JSON数据,
在将每个数组存储在变量中(没有必要)之后,在第三部分中,我对数组的每个元素进行了console.log
/**
*Part 1
*/
var data = JSON.parse(`{"line_items": {"AMS Upgrade": [{"Total": 30667.303111791967}, {"% Complete to end": 1.0}, {"value claimed": 25799.788761888347}], "BMS works": [{"Total": 35722.8761704046}, {"% Complete to end": 0.1}, {"value claimed": 3572.2876170404597}]}}`);
/**
*Part 2
*/
var amsUpgrade = data['line_items']['AMS Upgrade'];
console.log('AMS Upgrade : ', amsUpgrade);
/**
*Part 3
*/
console.log('AMS Upgrade Total : ', amsUpgrade[0]['Total']);
console.log('AMS Upgrade % Complete to end : ', amsUpgrade[1]['% Complete to end']);
console.log('AMS Upgrade value claimed', amsUpgrade[2]['value claimed']);
var bmsWorks = data['line_items']['BMS works'];
console.log('BMS works : ', bmsWorks);
console.log('BMS works Total : ', bmsWorks[0]['Total']);
console.log('BMS works % Complete to end : ', bmsWorks[1]['% Complete to end']);
console.log('BMS works value claimed', bmsWorks[2]['value claimed']);