我正在使用Google Apis客户端库。
我不明白如何根据文件夹名称或文件夹ID获取文件列表,例如:-
驱动器文件夹结构
Main =>
- Demo 1
- img.png
- img2.png
- Demo 2
- img_Demo 2.png
- img2_Demo 2.png
- Demo 3
- img_Demo 3.png
- img2_Demo 3.png
现在我使用以下代码获取主文件夹列表和ID
<?php
// include your composer dependencies
require_once 'vendor/autoload.php';
#https://developers.google.com/api-client-library/php/auth/web-app
$client = new Google_Client();
$client->setAuthConfig('client_secret.json');
$client->addScope(Google_Service_Drive::DRIVE_METADATA_READONLY);
$client->setAccessToken('AccessToken');
$drive = new Google_Service_Drive($client);
$files_list = $drive->files->listFiles(array())->getFiles($optParams);
echo "<pre>";
print_r($files_list);
exit;
?>
我得到以下输出:
Array
(
[0] => Google_Service_Drive_DriveFile Object
(
[id] => 1LKMiCuI3OlUYrFlQnl
[imageMediaMetadataType:protected] => Google_Service_Drive_DriveFileImageMediaMetadata
[imageMediaMetadataDataType:protected] =>
[isAppAuthorized] =>
[kind] => drive#file
[lastModifyingUserType:protected] => Google_Service_Drive_User
[mimeType] => application/vnd.google-apps.folder
[name] => main
)
)
答案 0 :(得分:1)
File.list具有q参数,它将允许您search个文件。以下内容将返回所有父ID为1234567的文件,这些文件是您要查找的目录的文件ID。
'1234567' in parents
您可以将q参数作为optParams的一部分发送
$optParams = array( 'q' => "'1234567' in parents" );
$files_list = $drive->files->listFiles($optParams);