Question

public class tryget extends Activity
{
    TextView result1;
    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState)
    {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        Log.i("GET RESPONSE","result outside");
        try
        {
            HttpClient client = new DefaultHttpClient();  
            String getURL = "http://10.0.2.2:8888/mainserver1/androidservlet";
            HttpGet get = new HttpGet(getURL);
            HttpResponse responseGet = client.execute(get);  
            HttpEntity resEntityGet = responseGet.getEntity();  
            if (resEntityGet != null)
            {  
                InputStream is = resEntityGet.getContent();
                String s=is.toString();
                byte[] bytes =s.getBytes();

                ObjectInputStream in = new ObjectInputStream(new ByteArrayInputStream(bytes));

                String result =  (String) in.readObject();


                result1=(TextView)findViewById(R.id.result1);
                result1.setText(s);
                result1.findViewById(R.id.result1);


                //do something with the response
                //Log.i("GET RESPONSE",EntityUtils.getContentCharSet(resEntityGet));
                Log.i("GET RESPONSE",result);
                // in.close();
                is.close();  
            }
        }
        catch (Exception e)
        {
            e.printStackTrace();
        }
    }
}

我可以看到应用程序在模拟器中运行但是我看不到包含“result”值的文本字段在其空间中没有出现，并且当我运行服务器活动的代码时，Logcat显示IO.exception。

Answer 1

您无法看到“结果”的值，因为在它到达Log.i("GET RESPONSE",result);之前抛出了异常。修复抛出Exception中描述的问题，您将看到结果。

此外，不要在e.printStackTrace();中写catch，而是写下这样的内容：

Log.e("MY TAG", e.toString(), e);

Logcat中的IO.Exception，但我可以看到应用程序正在运行

1 个答案: