Question

我有以下查询：

select s.ScreenID, s.ScreenName, ps.ScheduleDate
from Screens s
left join PerformanceSchedules ps on ps.ScreenID = s.ScreenID
where s.TheatreID = 2 and ((ps.ScheduleDate not between convert(datetime, '2019-08-02 14:00:00.000') and convert(datetime, '2019-08-02 20:00:00.000')) or (ps.ScheduleDate is null))

查询结果为：

ScreenID    ScreenName  ScheduleDate
4           Screen 1    2019-08-02 15:00:00.000
5           Screen 2    2019-08-02 15:00:00.000
6           Screen 3    NULL

通常，它只应返回屏幕3，而不返回其他两个，因为两者的ScheduleDate在时间范围内。

结果应为：

6   Screen 3    NULL

Answer 1

我怀疑您真的想要：

select s.ScreenID, s.ScreenName, ps.ScheduleDate
from Screens s left join
     PerformanceSchedules ps
     on ps.ScreenID = s.ScreenID and
        ps.ScheduleDate between convert(datetime, '2019-08-02 14:00:00.000', 121) and convert(datetime, '2019-08-02 20:00:00.000', 121)
where s.TheatreID = 2 and
      ps.ScreenID is null;

这将返回在这些时间之间没有计划日期的屏幕。

SQL语句//与日期时间之间

1 个答案: