Question

当前正在处理作业，我需要读取一个数字文件，并显示数字的总数，偶数的总数，奇数的总数以及这三者的平均值。我目前正在努力寻找偶数和奇数的平均值。我必须显示偶数和奇数的平均值。我通过使用parseInt将读入的数字字符串转换为ints来找到总平均值，因此我可以计算平均值，但是当我尝试对偶数和奇数进行相同操作时，我无法使它起作用

这是我当前的代码：

public class Homework1 {
  public static void main(String[] args) throws IOException {
  // reads file in
  File num = new File("numbers.txt");
  Scanner inputFile = new Scanner(num);
  // creates rounding object
  DecimalFormat rounding = new DecimalFormat("#.##");
  // neccesary variables
  int count = 0;
  double numbers =0;
  int evenNum =0;
  int oddNum =0;
  double avg;
  double evenAvg;
  double oddAvg;
  double sum = 0.0;
  double evenSum = 0.0;
  double oddSum = 0.0;

  // reads in numbers file until last line is read
  while(inputFile.hasNext())
  {
         String nums = inputFile.nextLine();
  // converts string to ints so numbers can be added
         sum += Integer.parseInt(nums);
  // converts string to ints to so odd/even nums can be distinguished
         numbers = Integer.parseInt(nums);
  // updates total number count
         count++;

  // separates evens from odds
  if(numbers % 2 == 0)
      {
         evenNum++;
         evenSum += Integer.parseInt(nums);
      }

      else
         oddNum++;
         evenSum += Integer.parseInt(nums);
   } 

   // calculates total num average
   avg = sum/count; 

  // evenAvg = 
 //  oddAvg =  

   // output of credentials and results

   System.out.println("There are " +count+ " numbers in the file"+"\n");
   System.out.println("There are " +evenNum+ " even numbers"+"\n");
   System.out.println("There are " +oddNum+ " odd numbers"+"\n");
   System.out.println("The total average value is " +rounding.format(avg)+"\n"); 
   System.out.println("The odd number average is " +rounding.format(evenAvg)+"\n");
   System.out.println("The even number average is " +rounding.format(oddAvg)+"\n");

}

输出：

There are 982 numbers in the file

There are 474 even numbers

There are 508 odd numbers

The total average value is 50362.43

Answer 1

好的，所以我更正了if / else语句并添加了方括号，这解决了我遇到的问题

oddNum++;
         oddSum += Integer.parseInt(nums);

读取number.txt文件并求平均值

1 个答案: