Question

目标：

在第1周中获取ID登录，然后在第2周中登录多少个ID。重新开始第2周至第3周的逻辑。然后是第3周和第4周，依此类推...该练习需要每周进行。需要按队列（即他们订阅的月份和年份）对ID进行细分。

故事：

第一个表（成员）具有电子邮件及其创建日期。第二个表（登录表）是登录活动。首先，我需要按创建日期（月-年）对电子邮件进行分组以创建群组。然后，每个群组的每周登录活动比较。可能吗要使该查询每周动态？

输出： 结果应如下所示：

+--------+--------+--------+--------+---------+
| Cohort | 2019-1 | 2019-2 | 2019-3 | 2019-4  |...
+--------+--------+--------+--------+---------+
| 2018-3 |   7000 |   6800 |    7400|    7100 |...
| 2018-4 |   6800 |   6500 |    8400|    8000 |...
| 2018-5 |   9500 |   8000 |    6400|    6200 |...
| 2018-6 |   9100 |   8500 |    8000|    7800 |...
| 2018-7 |  10000 |   8000 |    7000|    6800 |...
+--------+--------+--------+--------+---------+

我尝试过的事情：

SELECT CONCAT(DATEPART(YEAR,m.date_created),'-',DATEPART(MONTH,m.date_created)) AS Cohort
    ,CONCAT(subquery.[YYYY],'-',subquery.[ISO])                     AS YYYY_ISO
    ,m.email
FROM member as m
INNER JOIN (SELECT DATEPART(YEAR,log.login_time)    AS [YYYY]
        ,DATEPART(ISO_WEEK,log.login_time)  AS [ISO]
        ,log.email
        ,ROW_NUMBER()
            OVER(PARTITION BY 
            DATEPART(YEAR,log.login_time), 
            DATEPART(ISO_WEEK,log.login_time),
            log.email
        ORDER BY log.login_time ASC) AS Log_Rank
        FROM login AS log
        WHERE CAST(log.login_time AS DATE) >= '2019-01-01'
        ) AS subquery ON m.email=subquery.email AND Log_Rank = 1
ORDER BY cohort

样本数据：

CREATE TABLE member
    ([email] varchar(50), [date_created] Datetime)

CREATE TABLE login
    ([email] varchar(50), [login_time] Datetime)

INSERT INTO member
VALUES
    ('player123@google.com', '2018-03-01 05:00:00'),
    ('player999@google.com', '2018-04-12 12:00:00'),
    ('player555@google.com', '2018-04-25 20:15:00')

INSERT INTO login
VALUES
    ('player123@google.com', '2019-01-07 05:30:00'),
    ('player123@google.com', '2019-01-08 08:30:00'),
    ('player123@google.com', '2019-01-15 06:30:00'),
    ('player999@google.com', '2019-01-08 11:30:00'),
    ('player999@google.com', '2019-01-10 07:30:00'),
    ('player555@google.com', '2019-01-08 04:30:00')

按同类群组每周动态比较

0 个答案: