Question

我目前正在尝试制作一个简单的21点程序，该程序是单人游戏，只有1-10张卡片。我遇到的问题是，每当我第三次要求购买新卡时，都无法正确汇总我的卡。该程序也无法正确重启这里是输出示例：

Welcome to Blackjack!
Here are your first cards: 10, 2
Your total is 12.
Would you like to draw another card? (y/n)
y
You got a new card with a value of 6.
Your total is now 18.
Would you like to draw another card? (y/n)
y
You got a new card with a value of 4.
Your total is now 16.
Would you like to draw another card? (y/n)
n
Welcome to Blackjack!
Here are your first cards: 6, 4
Your total is 10.
Would you like to draw another card? (y/n)

我尝试过使用do-while循环，以便每次总数<21时都会要求换一张新卡，但结局相同。我不知如何解决这个问题。

#include <iostream>
#include <ctime>
#include <cstdlib>
using namespace std;

int getCard(int);

int main()
{
    srand(time(0));
    int total, card1, card2, newTotal = 0;
    char choice, playAgain = 'y';

    while (playAgain == 'y')
    {
        cout << "Welcome to Blackjack!\n";
        card1 = rand() % 10 + 1;
        card2 = rand() % 10 + 1;
        total = card1 + card2;
        cout << "Here are your first cards: " << card1 << ", " << card2 << endl;
        cout << "Your total is " << total << "." << endl;

        cout << "Would you like to draw another card? (y/n)\n";
        cin >> choice;

         while (choice == 'y')
         {
             newTotal = getCard(total);

             if (newTotal > 21)
             {
                 cout << "Bust!" << endl;
                 choice = 'n';
             }

             else if (newTotal < 21)
             {
                cout << "Would you like to draw another card? (y/n)\n";
                cin >> choice;
             }
             else
             {
                 cout << "Congratulations, you won!\n";
                 choice = 'n';
             }
         }
      }

    cout << "Would you like to play again? (y/n)\n";
    cin >> playAgain;

    return 0;
}

int getCard(int total)
{ 
    int addCard, newTotal;
    addCard = rand() % 10 + 1;
    newTotal = total + addCard;
    cout << "You got a new card with a value of " << addCard << "." << 
    endl;
    cout << "Your total is now " << newTotal << "." << endl;
    return newTotal;
}

该程序将以两张卡开始播放器，然后询问他们是否要抽出另一张。如果他们输入“ y”，那么它将这样做并合计卡片。如果他们拒绝，那么游戏就结束了。如果他们回答“是”，而新卡的总数大于21，则返回“破产”。如果总数变为21，则告诉玩家获胜。在每局游戏结束时，都应询问玩家是否愿意再次玩。

Answer 1

您的逻辑存在问题。

首先，newTotal = getCard(total);应该为total = getCard(total);，以便更新total（因此，您到处都应将newTotal替换为total）。通过使用此newTotal变量，您总是可以丢弃while循环中的前一个总数，并从循环前定义为total = card1 + card2;的那个开始。
第二，while (playAgain == 'y')始终为真，因为您没有从此循环内部更新playAgain（因此您永远不会到达询问用户是否要再次播放的代码）。在此循环内移动以下两行：

cout << "Would you like to play again? (y/n)\n";
cin >> playAgain;

像这样：

#include <iostream>
#include <ctime>
#include <cstdlib>
using namespace std;

int getCard(int);

int main()
{
    srand(time(0));
    int total, card1, card2, newTotal = 0;
    char choice, playAgain = 'y';

    while (playAgain == 'y')
    {
        cout << "Welcome to Blackjack!\n";
        card1 = rand() % 10 + 1;
        card2 = rand() % 10 + 1;
        total = card1 + card2;
        cout << "Here are your first cards: " << card1 << ", " << card2 << endl;
        cout << "Your total is " << total << "." << endl;

        cout << "Would you like to draw another card? (y/n)\n";
        cin >> choice;

         while (choice == 'y')
         {
             total = getCard(total);

             if (total > 21)
             {
                 cout << "Bust!" << endl;
                 choice = 'n';
             }

             else if (total < 21)
             {
                cout << "Would you like to draw another card? (y/n)\n";
                cin >> choice;
             }
             else
             {
                 cout << "Congratulations, you won!\n";
                 choice = 'n';
             }
         }

        cout << "Would you like to play again? (y/n)\n";
        cin >> playAgain;
    }

    return 0;
}

int getCard(int total)
{
    int addCard, newTotal;
    addCard = rand() % 10 + 1;
    newTotal = total + addCard;
    cout << "You got a new card with a value of " << addCard << "." << endl;
    cout << "Your total is now " << newTotal << "." << endl;
    return newTotal;
}

弄清楚如何修复C ++ Blackjack程序的问题

1 个答案: