Question

我一直在尝试测试此签到表是否确实适用于学校项目，并且不断收到错误消息，指出存在意外的“;”。或'{'，但我不知道我做错了什么。我非常感谢您的帮助。：）

我尝试删除代码的特定部分，以查看是否只是问题所在，但是随后会出现新的错误，并出现类似的问题。我也尝试编辑错误部分附近的代码，但这似乎也不起作用。

<?php
if (isset($_POST['submit'])){

    include_once'dbh.inc.php'; 

    $first = mysqli_real_escape_string($conn, $_POST['first']);
    $last = mysqli_real_escape_string($conn, $_POST['last']);
    $email = mysqli_real_escape_string($conn, $_POST['email']);
    $uid = mysqli_real_escape_string($conn, $_POST['uid']);
    $pwd = mysqli_real_escape_string($conn, $_POST['pwd']);

    //Error handlers
    //Check if everything has been filled out
    if (empty($first) || (empty($last) || (empty($email) || (empty($uid) || 
(empty($pwd))
    {

    }else{
        //check if input characters are valid
            if (!preg_match("/^[a-zA-Z]*$/", $first) || !preg_match("/^[a- 
            zA-Z]*$/", $last))
            {
                header("Location: ../signup.php"); 
                exit();
            }else{ 
                //check if email is valid
                if (!filter_var($email, FILTER_VALIDATE_EMAIL)){ 
                    header("Location: ../signup.php"); 
                    exit();
                }else{ 
                    $sql = "SELECT * FROM users WHERE user_uid ='$uid'";
                    $result = mysqli_query($conn, $sql);
                    $resultCheck = mysqli_num_rows($result);

                    if ($resultCheck > 0){ 
                        header("Location: ../signup.php"); 
                        exit();
                    }else{ 
                        //Hashing the password
                        $hashedPwd = password_hash($pwd, PASSWORD_DEFAULT); 
                        //Insert the user into the database
                        $sql = "INSERT INTO users (user_first, user_last, 
user_email, user_uid, user_pwd) VALUES ('$first', '$last', '$email', 
'$uid', '$hashedPwd');";
                        $result = mysqli_query($conn, $sql);
                        header("Location: ../signup.php"); 
                        exit();
                    }
                }
            }
        }

    }else{
        header("Location: ../signup.php");
        exit(); 
    }

预期结果是注册表可以正常工作并显示在数据库中，而没有任何语法错误。

为什么我在这段代码中不断出现parse error：syntax error？

0 个答案: