Question

我从网络上获取数据以显示所有学生名单，但遇到此错误。如何解决？

错误：“ com.android.volley.ParseError：org.json.JSONException：java.lang.String类型的值br无法转换为JSONArray”

这是我的代码。

MainActivity.java

public class MainActivity extends AppCompatActivity {

String urlGetData = "http://demokl.atwebpages.com/getdata.php";

private void GetData(String url) {
    RequestQueue requestQueue = Volley.newRequestQueue(this);
    JsonArrayRequest jsonArrayRequest = new JsonArrayRequest(Request.Method.GET, url, null,
            new Response.Listener<JSONArray>() {
                @Override
                public void onResponse(JSONArray response) {
                    // Get Json object from php page
                    studentArrayList.clear();
                    for (int i = 0; i < response.length(); i++) {
                        try {
                            JSONObject jsonObject = response.getJSONObject(i);
                            studentArrayList.add(new Student(jsonObject.getInt("ID"),
                                    jsonObject.getString("FullName"),
                                    jsonObject.getInt("YearOfBirth"),
                                    jsonObject.getString("Address")));
                        } catch (JSONException e) {
                            e.printStackTrace();
                        }
                    }
                    studentAdapter.notifyDataSetChanged();
                }
            },
            new Response.ErrorListener() { // Error link or server
                @Override
                public void onErrorResponse(VolleyError error) {
                    Toast.makeText(MainActivity.this, "Error !", Toast.LENGTH_SHORT).show();
                    Log.d("AAA", error.toString());

                }
            });
    requestQueue.add(jsonArrayRequest);
}

getdata.php

<?php

require "dbCon.php";
// Get All data in student table
$query = "SELECT * FROM studenttable"; // student table
$data = mysqli_query($connect, $query);

// Create class Student
class Student {
    function Student($id, $fullname, $yearOfBirth, $address) {
        $this -> ID = $id;
        $this -> FullName = $fullname;
        $this -> YearOfBirth = $yearOfBirth;
        $this -> Address = $address;
    }
}

// Push each element to array 
$arrayStu = array();

while ($row = mysqli_fetch_assoc($data)) {
    array_push($arrayStu, new Student($row['id'], $row['fullname'], $row['yearofbirth'], $row['address']));
}

// Export array to JSON data
echo json_encode($arrayStu);

？>

dbCon.php

<?php 

$connect = mysqli_connect("fdb26.awardspace.net", "2953966_demo", "khanhlee93", "2953966_demo"); // (server, name, pass, dbname)
mysqli_query($connect, "SET NAMES 'utf8'");

?>

Answer 1

更改请求类型自

JsonArrayRequest jsonArrayRequest = new JsonArrayRequest(Request.Method.GET, url, null,
        new Response.Listener<JSONArray>()

收件人

StringRequest stringRequest = new StringRequest(Request.Method.GET, url, new Response.Listener<String>()

错误：“类型java.lang.String的值br不能转换为JSONArray”

1 个答案: