Question

如何生成每个元素都不相同的4X4 2D数组表？

这是我的代码：

public class Game {
public static void main(String[] args) {
    int gameboard[][] = new int[4][4];
    for (int row=0; row < gameboard.length; row++) {
        for (int col=0; col < gameboard[row].length; col++) {
            gameboard[row][col] = ((int)(1+Math.random() * 16));
            System.out.printf("%-4d",gameboard[row][col]);
        }
        System.out.println();
        }
      }

}

Answer 1

您可以使用Set第一得到没有重复，然后一个List容易地访问它们

Set<Integer> set = new LinkedHashSet<>();
int gameboard[][] = new int[4][4];

while(set.size() != 4*4){
    set.add((int)(1+Math.random() * 16));
}

List<Integer> list = new ArrayList<>(set);

for (int row=0; row < gameboard.length; row++) {
    for (int col=0; col < gameboard[row].length; col++) {
        gameboard[row][col] = list.get(row*gameboard.length + col);
        System.out.printf("%-4d",gameboard[row][col]);
    }
    System.out.println();
    }
  }

Answer 2

您只需要在以下位置放置一个控件即可：

 int a == gameboard[row][col];

 for (int row=0; row < gameboard.length; row++) {
     for (int col=0; col < gameboard[row].length; col++) {
             gameboard[row][col] = ((int)(1+Math.random() * 16));
             if(gameboard[row][col] == a){
                 col = col - 1; 
             }
     }
 }

Answer 3

解决方案1：

public static void main(String[] s1) throws Exception {
    int gameboard[][] = new int[4][4];
    Set<Integer> mySet = new HashSet<>();

    for (int row = 0; row < gameboard.length; row++) {
        for (int col = 0; col < gameboard[row].length; col++) {
            int randNum = (int) (1 + Math.random() * 16);

            while (mySet.contains(randNum)) {
                randNum = (int) (1 + Math.random() * 16);
            }
            mySet.add(randNum);

            gameboard[row][col] = randNum;
            System.out.printf("%-4d", gameboard[row][col]);
        }
        System.out.println();
    }
}

在每次迭代中，我们检查 set 中是否存在生成的随机数。如果存在，那么我们将循环运行，直到获得集合中不存在的其他随机数。

解决方案2：

List<Integer> myList = IntStream.range(1, 17).boxed().collect(Collectors.toList());
Collections.shuffle(myList);

for (int row = 0; row < gameboard.length; row++) {
    for (int col = 0; col < gameboard[row].length; col++) {
        gameboard[row][col] = myList.get(row * gameboard.length + col);
        System.out.printf("%-4d", gameboard[row][col]);
    }
    System.out.println();
}

在这里，我们生成一个数字列表，然后使用 Collections.shuffle（）对其进行洗牌。现在，我们遍历多维数组，并将列表的值分配给该数组。

如何生成不重复的数字二维数组表？

3 个答案: