Question

假设我有两个数组，它们是：

var oldArray = [
  {name: 'Trump', isRunning: false},
  {name: 'Cruz', isRunning: false},
  {name: 'saga', isRunning: false}
];

var newArray = [
  {name: 'Trump', isRunning: true},
  {name: 'Cruz', isRunning: true},
  {name: 'mega', isRunning: true},
  {name: 'alpha', isRunning: true},
  {name: 'beta', isRunning: true},
  {name: 'oliverspost', isRunning: true}
];

我想从newArray中删除所有重复的对象，并替换为与带有oldArray的对应对象。同样，如果newArray中不存在，则oldArray中的任何对象会将其isRunning时间更改为“ True”，并将其推送到newArray。

预期结果：

[
  {name: 'Trump', isRunning: true},
  {name: 'Cruz', isRunning: true},
  {name: 'mega', isRunning: true},
  {name: 'alpha', isRunning: true},
  {name: 'beta', isRunning: true},
  {name: 'daya', isRunning: true},
  {name: 'oliverspost', isRunning: true},
  {name: 'saga', isRunning: true}
]

Answer 1

var oldArray = [
  {name: 'Trump', isRunning: false},
  {name: 'Cruz', isRunning: false},
  {name: 'saga', isRunning: false}
];

var newArray = [
  {name: 'Trump', isRunning: true},
  {name: 'Cruz', isRunning: true},
  {name: 'mega', isRunning: true},
  {name: 'alpha', isRunning: true},
  {name: 'beta', isRunning: true},
  {name: 'oliverspost', isRunning: true}
];

newArrayNamesOnly = newArray.map(value => value.name);

oldArray.map(value => {
    let currentName = value.name;
    if (!newArrayNamesOnly.includes(currentName)){
        newArray.push({name: currentName, isRunning: true});
        newArrayNamesOnly.push(currentName);
    }
});

console.log(newArray);

Answer 2

var oldArray = [
    {name: 'Trump', isRunning: false},
    {name: 'Cruz', isRunning: false},
    {name: 'saga', isRunning: false}
];

var newArray = [
   {name: 'Trump', isRunning: true},
   {name: 'Cruz', isRunning: true},
   {name: 'mega', isRunning: true},
   {name: 'alpha', isRunning: true},
   {name: 'beta', isRunning: true},
   {name: 'oliverspost', isRunning: true}
];


var currentArray = [...oldArray,...newArray]
var obj = {};

for ( var i=0, len=currentArray.length; i < len; i++ )
    obj[currentArray[i]['name']] = currentArray[i];
Object.keys(obj).map((i)=> obj[i])

如何从比较oldArray和newArray的对象数组中删除重复项？

2 个答案: